Converting standard form to standard form of an ellipse

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SUMMARY

The discussion focuses on converting the equation x² + 4y² - 8y - 6x + 9 into the standard form of an ellipse. The correct standard form is identified as ((x - 3)² / (2)²) + ((y - 2)² / (1)²) = 1. The confusion arose from the absence of an equality sign in the original equation, which was clarified by rewriting it as x² + 4y² - 8y - 6x + 9 = 0. The participant successfully resolved their misunderstanding regarding the constant term in the equation.

PREREQUISITES
  • Understanding of conic sections, specifically ellipses
  • Familiarity with completing the square method
  • Knowledge of standard forms of conic equations
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Learn how to complete the square for quadratic equations
  • Study the properties and characteristics of ellipses
  • Explore the derivation of the standard form of conic sections
  • Practice converting other conic equations into standard forms
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Students studying algebra, particularly those focusing on conic sections, as well as educators teaching the principles of ellipses and their equations.

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Homework Statement


x^2+4y^2-8y-6x+9 convert this equation to the standard form of an ellipse and identify the foci, the middle point,

Homework Equations


x^2/b^2+y^2/b^2


The Attempt at a Solution



Ellipse-----> My standard form of this ellipse ((x-3)^2/(2)^2)+((y-2)^2/(1^2))-4
I worked at this as the form of the ellipse but i just do not understand what i am doing wrong because the -4 is there.

 
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x^2+4y^2-8y-6x+9 isn't an 'equation'. There's no '=' sign. Neither is x^2/b^2+y^2/b^2. If you write the standard form as x^2/b^2+y^2/b^2=1 and the form given as x^2+4y^2-8y-6x+9=0, it might be clearer what you should do with the -4.
 
Thanks so much! Yeah i left out some pretty important stuff.. I got the answer now. Appreciate it!
 

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