Converting standard form to standard form of an ellipse

[thearn]

Homework Statement

x^2+4y^2-8y-6x+9 convert this equation to the standard form of an ellipse and identify the foci, the middle point,

Homework Equations

x^2/b^2+y^2/b^2

The Attempt at a Solution

Ellipse-----> My standard form of this ellipse ((x-3)^2/(2)^2)+((y-2)^2/(1^2))-4
I worked at this as the form of the ellipse but i just do not understand what i am doing wrong because the -4 is there.

 

[Dick]

x^2+4y^2-8y-6x+9 isn't an 'equation'. There's no '=' sign. Neither is x^2/b^2+y^2/b^2. If you write the standard form as x^2/b^2+y^2/b^2=1 and the form given as x^2+4y^2-8y-6x+9=0, it might be clearer what you should do with the -4.

 

[thearn]

Thanks so much! Yeah i left out some pretty important stuff.. I got the answer now. Appreciate it!