The discussion revolves around calculating the length of an aluminium wire needed to achieve a specific resistance using the formula l = RA/rho. The problem involves converting the diameter of the wire into a usable form for this calculation.
Participants are actively clarifying the definitions of the variables involved in the equation and exploring the relationship between diameter and cross-sectional area. There is ongoing inquiry into how to proceed with the calculations based on these definitions.
The diameter of the wire is given as 0.5 mm, and there is a focus on understanding the necessary conversions and implications for the resistance calculation. The resistivity of the material is also specified, which may influence the discussion.
vikz said:Homework Statement
An aluminium wire has diameter 0.5 mm and resistivity 2.8 X 10-6 Ohm cm. How much lenth of this wire is required to make a 20 Ohm coil?
Please tell me how to convert Diameter 0.5mm? what's the procedure?
After that I can directly apply-
l = RA/rho
sjb-2812 said:What do each of your variables signify, R, A, rho?
vikz said:R = Resistance
rho= Electrical Resistivity of the material of the conductor.
A = Area of cross-section
gneill said:Which of those variables depends directly the radius (or diameter) of the wire?