vikz said:Homework Statement
An aluminium wire has diameter 0.5 mm and resistivity 2.8 X 10-6 Ohm cm. How much lenth of this wire is required to make a 20 Ohm coil?
Please tell me how to convert Diameter 0.5mm? what's the procedure?
After that I can directly apply-
l = RA/rho
sjb-2812 said:What do each of your variables signify, R, A, rho?
vikz said:R = Resistance
rho= Electrical Resistivity of the material of the conductor.
A = Area of cross-section
gneill said:Which of those variables depends directly the radius (or diameter) of the wire?
The equation is l = RA/rho, where l represents the length, R is the radius, A is the cross-sectional area, and rho is the density.
R can be determined by dividing the diameter of the object by 2. This is because the radius is half the length of the diameter.
The equation is used to convert the diameter of an object to its length. This is especially useful in scientific experiments and calculations involving cylindrical objects.
Yes, the equation can be used for any object with a cylindrical shape, as long as the density (rho) is known or can be measured.
No, this equation is specifically for converting diameter to length. To convert length to diameter, the equation would be d = 2R, where d is the diameter and R is the radius.