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Converting the diameter for the equation l = RA/rho

  1. Jun 28, 2011 #1
    1. The problem statement, all variables and given/known data

    An aluminium wire has diameter 0.5 mm and resistivity 2.8 X 10-6 Ohm cm. How much lenth of this wire is required to make a 20 Ohm coil?

    Please tell me how to convert Diameter 0.5mm? what's the procedure?
    After that I can directly apply-
    l = RA/rho
     
  2. jcsd
  3. Jun 28, 2011 #2

    What do each of your variables signify, R, A, rho?
     
  4. Jun 28, 2011 #3
    R = Resistance
    rho= Electrical Resistivity of the material of the conductor.
    A = Area of cross-section

    SI unit of resistivity is Ohm m
     
    Last edited: Jun 28, 2011
  5. Jun 28, 2011 #4

    gneill

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    Staff: Mentor

    Which of those variables depends directly the radius (or diameter) of the wire?
     
  6. Jun 28, 2011 #5
    R is inversely propositional to 1/A
     
    Last edited: Jun 28, 2011
  7. Jun 28, 2011 #6

    gneill

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    Staff: Mentor

    Suppose that d=0.5mm is the diameter of the wire. What is the cross sectional area, A?
     
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