# Converting the diameter for the equation l = RA/rho

• vikz
In summary, the conversation discusses the use of an aluminium wire with a diameter of 0.5 mm and a resistivity of 2.8 X 10-6 Ohm cm to create a 20 Ohm coil. The individual asks for guidance on converting the diameter to determine the required length of the wire, and the variables R, A, and rho are explained. The conversation also mentions the inverse relationship between R and A, and the calculation of A given a diameter of 0.5 mm.
vikz

## Homework Statement

An aluminium wire has diameter 0.5 mm and resistivity 2.8 X 10-6 Ohm cm. How much lenth of this wire is required to make a 20 Ohm coil?

Please tell me how to convert Diameter 0.5mm? what's the procedure?
After that I can directly apply-
l = RA/rho

vikz said:

## Homework Statement

An aluminium wire has diameter 0.5 mm and resistivity 2.8 X 10-6 Ohm cm. How much lenth of this wire is required to make a 20 Ohm coil?

Please tell me how to convert Diameter 0.5mm? what's the procedure?
After that I can directly apply-
l = RA/rho

What do each of your variables signify, R, A, rho?

sjb-2812 said:
What do each of your variables signify, R, A, rho?

R = Resistance
rho= Electrical Resistivity of the material of the conductor.
A = Area of cross-section

SI unit of resistivity is Ohm m

Last edited:
vikz said:
R = Resistance
rho= Electrical Resistivity of the material of the conductor.
A = Area of cross-section

Which of those variables depends directly the radius (or diameter) of the wire?

gneill said:
Which of those variables depends directly the radius (or diameter) of the wire?

R is inversely propositional to 1/A

Last edited:
Suppose that d=0.5mm is the diameter of the wire. What is the cross sectional area, A?

## 1. What is the equation for converting diameter to length?

The equation is l = RA/rho, where l represents the length, R is the radius, A is the cross-sectional area, and rho is the density.

## 2. How do I determine the value of R in the equation?

R can be determined by dividing the diameter of the object by 2. This is because the radius is half the length of the diameter.

## 3. What is the purpose of using the equation l = RA/rho?

The equation is used to convert the diameter of an object to its length. This is especially useful in scientific experiments and calculations involving cylindrical objects.

## 4. Is this equation applicable to all types of objects with a cylindrical shape?

Yes, the equation can be used for any object with a cylindrical shape, as long as the density (rho) is known or can be measured.

## 5. Can this equation be used to convert length to diameter?

No, this equation is specifically for converting diameter to length. To convert length to diameter, the equation would be d = 2R, where d is the diameter and R is the radius.

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