Converting to unit impulse function

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To convert the triangular function tri(t-1) to a unit impulse function, one must first understand that tri(t) represents a triangle waveform that rises and then falls. The conversion involves using ramp functions to construct the triangle, specifically by combining a ramp function that rises and another that decreases. The discussion suggests that tri(t-1) can be expressed as ramp(t) - ramp(t-2), which simplifies the process of finding the Laplace transform. The Laplace transform of the modified function can then be computed using standard techniques for the individual ramp functions. Understanding these conversions is crucial for effectively applying the Laplace transform to piecewise functions.
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I was wondering how do you go about converting something like tri(t-1) to the unit impulse function. How do you convert any function to a unit impulse function?

More specifically I'm trying to find the Laplace transform of x(t)=[tri(t-1)]e^(-3t)

And I was told you have to convert the tri(t-1) part to a unit impulse and then it become easy.
 
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I take it "tri" is a triangle function with ramp up from 0 to some value, then ramp down?

In that case, start with a ramp t, then figure what must be added to ramp down.

It's a bit like making a square/rectangular function by superimposing step functions, e.g. u(t) - u(t-1).
 
Astronuc said:
I take it "tri" is a triangle function with ramp up from 0 to some value, then ramp down?

In that case, start with a ramp t, then figure what must be added to ramp down.

It's a bit like making a square/rectangular function by superimposing step functions, e.g. u(t) - u(t-1).

So would it be ramp(t)+ramp(-t-1)

If that's the case, then how would you find the Laplace of that when it replaces tri(t-1)?
 
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