Converting Units in the Lorentz Force Law

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SUMMARY

The discussion focuses on converting units in the Lorentz Force Law, specifically demonstrating that the units of the expression 2πm/qB are equivalent to seconds. Participants emphasize the importance of understanding the units for mass (m), charge (q), and magnetic field (B in Tesla) to derive the time unit. The key relationship used is the Lorentz force law, F = q(E + v x B), which helps in establishing the dimensional analysis needed to solve the problem.

PREREQUISITES
  • Understanding of the Lorentz Force Law, F = q(E + v x B)
  • Knowledge of unit conversions for mass (kilograms), charge (coulombs), and magnetic field (Tesla)
  • Familiarity with dimensional analysis techniques
  • Basic algebra skills for manipulating equations
NEXT STEPS
  • Study dimensional analysis in physics to better understand unit conversions
  • Learn about the properties and applications of the Lorentz Force Law
  • Explore the relationship between force, charge, and magnetic fields in electromagnetism
  • Review examples of unit conversions in physics problems
USEFUL FOR

Students in physics courses, particularly those studying electromagnetism, as well as educators looking for insights on teaching unit conversions and the Lorentz Force Law.

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Homework Statement



Hello, i am in physics 30 and my teacher gave our class a worksheet for homework and I am stuck on the last question. Could anyone help me out please? Thanks.

Here is the question: Show that the units of 2[tex]\pi[/tex]m/ qB are equivalent to seconds.


How can I get the unit for time (s) from that? what do I have to show?


Homework Equations





The Attempt at a Solution



I tried using Fc = Fm but I don't get how 2[tex]\pi[/tex] is used in the equation? Or does it even have an effect and is there just as a constant with no units.
 
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Welcome dulask :smile: Start by writing out all of the units for each symbol in the expression
[tex]\frac{2\pi m}{qB}[/tex]

I do not know what any of them are just by looking at them. I could venture a guess, but I rather not :wink:
 
This problem is kinda annoying as B is in Tesla, q is a charge, m is a mass right? Well here's a nice little trick:

Do you know the Lorentz force law? F = q(E + v x B)? On one side is a force, something with units you should know and are far more comfortable with. On the other side, it has these crazy coulomb and tesla units! I'll assume you may not have gone over it but basically, dimensionally F = qvB! From there you should be able to figure it out.
 

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