Convex Mirrors and Magnification

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Homework Help Overview

The discussion revolves around the calculation of image distance and magnification for an automobile positioned in front of a convex mirror, with a specified focal length. Participants are exploring the implications of sign conventions in optics, particularly for convex mirrors.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of magnification using the formula provided, while questioning the signs associated with the focal length and image distance for convex mirrors. There is an exploration of whether the image is real or virtual and how this affects the calculations.

Discussion Status

The conversation is active, with participants providing insights into the sign conventions and addressing discrepancies in the original poster's calculations. Some guidance has been offered regarding the correct application of the magnification formula, though there is no explicit consensus on the correct values to use.

Contextual Notes

There is mention of a marking program that may have contributed to confusion regarding the correctness of the answers provided. Participants are navigating through the implications of this potential error while discussing the fundamental concepts involved.

kc262
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Homework Statement


What is the image distance for an automobile 4.5 m in front of a convex miror with a 0.15 m focal length? I found this to be 0.155 m

The question I'm having a problem with is: What is the magnification?

Homework Equations



magnification = - (image distance/object distance)

The Attempt at a Solution



I thought it would simply be,
-[0.155m/4.5m] = -0.0344. But it's not.

Some help would be much appreciated
 
Last edited:
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kc262 said:
What is the image distance for an automobile 4.5 m in front of a convex miror with a 0.15 m focal length? I found this to be 0.155 m
Careful with signs. For a convex mirror, what sign will the focal length have?
 
Doc Al said:
Careful with signs. For a convex mirror, what sign will the focal length have?

I realized that because it is a convex mirror, the focal length would be negative. However the marking program marked my answer right. I was confused by this :confused: And because of this discrepancy, I am unsure of how to find the magnification.
 
Is the image real or virtual? (And therefore, is the image distance positive or negative?)
 
kc262 said:
I realized that because it is a convex mirror, the focal length would be negative.
Then how did you get an image distance of +0.155 m ? (See Redbelly98's comment.)
However the marking program marked my answer right. I was confused by this :confused:
Now I'm confused. Your first post seemed to indicate that you knew your answer was wrong.
And because of this discrepancy, I am unsure of how to find the magnification.
You find it just as you stated in your first post:
magnification = - (image distance/object distance)
But you need the correct image distance (correct in both magnitude and sign), of course.
 
ok.. i got it. Turns out there was an error/glitch with the marking program. I got the answer in the end. Thanks for everyone's help! :biggrin:
 

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