- #1

DaveMann

- 1

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## Homework Statement

The focal length between a person and his mirror that produces a magnification of 1.50 when his face is 12.0 cm away is 0.36 m. He then moves to a distance of 3.7 times the focal length away from her mirror. What is the magnification now?

## Homework Equations

di/do=m

1/f=1/di+1/do

## The Attempt at a Solution

I've been trying to work this out on paper for the last hour. When his distance is 2.6 times the focal length, the magnification is -0.62. I can't figure out why that is though. There seems to be 2 variables.