Convolution in a Continous Linear Time Invariant System

In summary: You might have to change the amplitude of the impulses so they don't all have the scaling factor of 1. I think that's what you're asking.In summary, it is possible to represent an analog input signal as a sum of scaled and shifted Dirac delta functions, but not as a sum of scaled and shifted unit impulse sequences. This is because discrete time signals can only be shifted by integer multiples of the sampling time, whereas continuous time signals can be shifted by any value. However, it is still possible to represent a discrete time signal as a sum of scaled and shifted unit impulses by adjusting the amplitude of the impulses.
  • #1
N.Saravanan
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Dear Experts,
For convolution to work any input signal we should be able to represent the input signal in terms of appropriately scaled and shifted unit impulses. This one holds good for discrete time system in which the input signal can be represented as sum of scaled shifted unit impulses. But is it possible to represent an analog input signal as sum of scaled and shifted unit impulse. If so how? Why I ask is unlike in discrete system for which the unit impulse has no width, the practical unit impulse in analog system has negligible width. The unit impulse signal raises to value 1 from 0 in a very short time interval and falls back to zero again. Sum of scaled and shifted unit impulses repeat this action at a faster rate. So if we represent an analog input signal by scaled and shifted unit impulses the representation is actually a signal which touches the zero axis at intermediate intervals. But the original input analog signal need not touch the zero axis. So won't the signal approximation in continuous time produce a distorted input signal. So if we convolve this distorted zero touching input signal will we get the actual response of a system to any input? Kindly please explain the concept.

Thank You,
N.Saravanan.
 
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  • #2
N.Saravanan said:
But is it possible to represent an analog input signal as sum of scaled and shifted unit impulse. If so how? Why I ask is unlike in discrete system for which the unit impulse has no width, the practical unit impulse in analog system has negligible width.
Yes that's true. What you can say is that digital samples approximate an analog signal.

How approximate? Think of the Fourier series representation of the analog signal. Digital samples preserve most features of the frequencies below 1/2 the sampling frequency, and a poor job of samples above that frequency. Indeed, you may need an anti-aliasing low-pass filter to remove those frequencies before sampling.
Beyond that, the accuracy of the approximation depends on the nature of the analog signal.
 
  • #3
A continuous waveform may be expressed as a sum of infinitely-many scaled and shifted Dirac delta functions, not unit impulses. A delta function is mis-named--it's not a true function but rather the limit of a series of functions such that its height is infinite height, its width zero and its area unity. You can read about how it works and how it relates to convolution integrals from Wikipedia or any of dozens of online explanations.
 
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  • #4
Hi Saravanan

The dirac pulse:

$$

\delta(t) = \begin{cases} \infty & \text{ $ t = 0 $} \\ 0 & \text{Otherwise} \end{cases}
$$
And its discrete time equivalent (equivalent in the sense that it plays much of the same role as the pulse) the unit impulse sequence:

$$
\delta[ n ] = \begin{cases}1 & \text{n = 0} \\ 0 & \text{Otherwise} \end{cases}
$$

Below are the following theorems:

1. All CT and DT functions can be expressed as a sum of scaled and shifted dirac pulses and unit impulse sequences:
$$
f(t) = \displaystyle \int_{-\infty}^{\infty} f(\tau) \cdot \delta(t - \tau) \,\,\,\, \text{d}\tau
$$
and
$$
x[ n ] = \displaystyle \sum_{k \to -\infty}^{k \to \infty} x[ k ] \cdot \delta[ n - k]
$$
If its a continuous time signal, you express is as a superposition of scaled and shifted dirac pulses, if its a discrete time signal, you express it as a sum of scaled and shifted unit impulse sequences.

I think its as simple as that, as to why it works, you can refer to the two properties below:

1. The unit area property of the dirac pulse and the unit sample sequence.
$$
\displaystyle \sum_{n \to -\infty}^{n \to \infty} \delta[ n ] = \displaystyle \int_{-\infty}^{\infty} \delta(t) \,\,\,\,\text{dt} = 1
$$
2- The sifting property of the dirac pulse and the unit sample sequence:
$$
f(t_{0}) = \displaystyle \int_{-\infty}^{\infty} f(t) \cdot \delta(t - t_{0} ) \,\,\, \text{dt}
$$
and
$$
x[ n_{0} ] = \displaystyle \sum_{k \to -\infty}^{k \to \infty} x[ k ] \cdot \delta[ k - n_{0} ]
$$

Is it possible to express an analogue signal as a sum of scaled and shifted discrete unit impulse sequences? I don't believe this is possible, because remember, all discrete signals are sampled signals of the originals, hence, shifting a discrete time signal is simply multiplying the sample period with some integer. So its not possible, because you can only shift between integer multiples of your sampling time!

But, it is perfectly possible to express a DT signal as a sum of scaled and shifted unit impulses.
 
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1. What is convolution in a continuous linear time invariant system?

Convolution in a continuous linear time invariant (LTI) system is a mathematical operation that describes the relationship between the input and output signals of a system. It involves multiplying the input signal by the impulse response of the system and integrating the resulting product over time.

2. Why is convolution important in signal processing?

Convolution is important in signal processing because it allows us to analyze and understand the behavior of a system in response to different inputs. It is also used for filtering, which is necessary for removing noise or unwanted components from a signal.

3. How is convolution different from correlation?

While convolution and correlation are both mathematical operations that involve multiplying and integrating signals, they are used for different purposes. Convolution describes the output of a system in response to an input, while correlation measures the similarity between two signals.

4. Can convolution be performed on non-linear or time-varying systems?

No, convolution is only applicable to linear and time-invariant systems. Non-linear systems do not follow the principle of superposition, which is necessary for convolution to be valid. Time-varying systems also violate the assumption of time-invariance, making convolution invalid.

5. How is convolution related to the frequency domain?

In the frequency domain, convolution is equivalent to multiplication. This means that convolution in the time domain can be performed as multiplication in the frequency domain, making it a useful tool for analyzing and manipulating signals. This relationship is described by the convolution theorem.

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