Cooling of water vapor - air mixture to T < 273K

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SUMMARY

Cooling a mixture of water vapor and air to temperatures below 273 K results in a complex phase equilibrium. At 280 K, water typically exists in both gaseous and liquid states, demonstrating the principles of phase equilibrium. When cooled below 273 K, some water vapor remains in the air due to saturation pressure, potentially transitioning into solid form. This phenomenon highlights the possibility of gas/solid equilibrium in atmospheric conditions.

PREREQUISITES
  • Understanding of phase equilibrium concepts
  • Knowledge of saturation pressure and its implications
  • Familiarity with thermodynamic principles
  • Basic principles of water states (solid, liquid, gas)
NEXT STEPS
  • Research the effects of temperature on phase transitions in water
  • Explore the concept of saturation pressure in detail
  • Study thermodynamic properties of water vapor and air mixtures
  • Investigate gas/solid equilibrium in atmospheric science
USEFUL FOR

Atmospheric scientists, environmental engineers, and anyone interested in the thermodynamics of water vapor and air mixtures.

mike133
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What happens if you cool the mixture of water vapor and air to the temperature lower than 273 K? Since saturation pressure is higher than 0 some vapor should stay in the air. In the solid form?
 
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At 280K, water can (and usually does on Earth!) simultanously exist in gaseous and liquid states, in equilibrium. No reason why you can't have a gas/solid equilibrium too.
 

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