I Coriolis force, real or just an illusion?

[jbriggs444]

hause high 50km at equator

C(equator)=2r x 3.14 = 2 x 6371km x 3.14 =40 009km / 24h = 1667km/h

C(ball)= 2r x 3.14 = 2 x (6371km+50km) x3.14 =40323km /24h = 1680km/h
1680-1667=13km/h

top of hause travel 13km/h faster then bottom...

so this 13km/h is additional velocity which ball have in east direction

with this information we can calcualte how far east will ball hit the ground....

Given the time of fall, yes. Note that the proposed calculation does not depend at all on the radius of the earth. The 6371 cancels out.

But that's the inertial frame calculation. In the rotating frame there is no difference in velocity. The explanation for the deviation in the landing point derives from Coriolis instead.

 

[A.T.]

so this 13km/h is additional velocity which ball have in east direction

with this information we can calcualte how far east will ball hit the ground....

Approximately. For a more precise calculation in the inertial frame you would find the intersection of the elliptical orbit with the curved surface.