MHB Cos Trig Identity: Deriving Formula for Circuits Analysis

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The discussion focuses on deriving a cosine trigonometric identity for the expression cos(A+B)cos(A+C) relevant to circuit analysis. It is noted that this expression can be transformed into a sum using the identity cos(A+B)cos(A+C) = 1/2 [cos(2A + B + C) + cos(B-C)]. This transformation is crucial for simplifying calculations in circuit analysis. Participants seek clarification on the derivation process and its applications. Understanding this identity can enhance problem-solving in electrical engineering contexts.
paulmdrdo1
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Hello. Do you guys know if there is an identity related to this expression

$$\cos(A+B)\cos(A+C)$$

If so, can you help me how to derive it? I need it for the derivation of the formula from my circuits analysis course. Thanks.
 
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Apparently, you can change it from a product to a sum like this:
$$\cos(A+B) \, \cos(A+C) = \frac12 \left[ \cos(2A + B + C) + \cos(B-C) \right].$$
Does that help?
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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