Cosine of Vector: Adjacent/Hypothenuse

  • Thread starter Thread starter Tiven white
  • Start date Start date
  • Tags Tags
    Cosine Vector
Click For Summary

Homework Help Overview

The discussion revolves around the concept of cosine in relation to vectors, specifically questioning the validity of statements regarding the cosine of a vector and its relationship to components and magnitude.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the definition of cosine in the context of vectors, questioning whether the cosine can be applied to vectors or if it is strictly an angular measure. There is also confusion regarding the terminology used, such as "opposite" and "adjacent," in relation to vector components.

Discussion Status

The discussion is active with participants questioning the original statement about cosine and its application to vectors. Some participants express confusion about the terminology and the nature of the question being posed, while others clarify that cosine is defined for angles rather than vectors.

Contextual Notes

There is a lack of clarity regarding the original question and the definitions being used, leading to varied interpretations of the statements about cosine and vectors.

Tiven white
Messages
58
Reaction score
0

Homework Statement


The cosine of a vector is equal to the opposite over its magnitude.

Homework Equations



The attempt at a solution[/b] the cosine is the ratio of the adjacent to the hypothenuse this is why i say it "came' is incorrect.
 
Physics news on Phys.org
What exactly was the original question?
 
haruspex said:
What exactly was the original question?
That is the ?,its a true or false
 
Tiven white said:
That is the ?,its a true or false
What statement is true or false?

Oh, I see. It's this statement that's being questioned:
The cosine of a vector is equal to the opposite over its magnitude.

Yes, it's an incorrect statement, as you pointed out.
 
Last edited:
NascentOxygen said:
What statement is true or false?


If the cosine of a vector is its y component over its magnitude?
 
It's not the vector which has a cosine. It's only angles which have cosines.
 
Tiven white said:

Homework Statement


The cosine of a vector is equal to the opposite over its magnitude.
If this really is the statement, I would not say it was either "true" or "false". I would just say it is non-sense! The function "cosine" is not [g]defined[/b] for vectors, only for angles or numbers. Further, saying "the opposite" is non-sense. "Opposite" is an adjective not a noun and cannot take the article "the".

Homework Equations



The attempt at a solution
the cosine is the ratio of the adjacent to the hypothenuse this is why i say it "came' is incorrect.
 
Just out of curiosity, what is
Tiven white said:
this is why i say it "came' is incorrect.
supposed to mean?
 
vela said:
Just out of curiosity, what is
[ C A M ]
supposed to mean?

cosine = adjacent ÷ magnitude ?
 
  • #10
Wouldn't that be correct?
 
  • #11
vela said:
Wouldn't that be correct?
Clearly, OP is a little confused.
 
  • #12
cosine

NascentOxygen said:
Clearly, OP is a little confused.


The question was asking whether the statement ' cosine means the y component of a vector over its magnitude'.
Is this true or false?
 
  • #13
Tiven white said:
The question was asking whether the statement ' cosine means the y component of a vector over its magnitude'.
Is this true or false?
Definitely false.
 

Similar threads

Replies
14
Views
2K
Replies
25
Views
2K
Replies
3
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K