There is a plane flying at 200 km/h and wants to drop a bomb on a car traveling 130 km/h which is 78.0m below the plane. at what angle should the bomb be released? the answer is 45 degrees.
sine law: SinA/a= SinB/b
cosine law: a^2=b^2+c^2+bcCosA
sine,cosine and tan trig ratios
The Attempt at a Solution
converted 78.0m to 0.078 km.
I have drawn out the vectors but have not been able to add them. Any help would be appreciated.