Could you explain the concepts behind this question

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The discussion centers on calculating the electrical resistance of a truncated cone using Ohm's Law. The resistance \( R \) is derived from the resistivity \( \rho \) and the geometry of the cone, leading to the formula \( R = \frac{\rho}{\pi} \cdot \frac{h}{ab} \). The current density is uniform across circular cross-sections, but varies along the cone's height. Understanding this relationship is crucial for solving the posed problem.

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I'm trying this question. i know that resistance is the concept of ohms law together with electric potential giving rise to V/I but i can't seem to know how to start. Please advice




A material of resistivity r is formed into the shape of a truncated cone of altitude h. The bottom end has radius b , and the top end has radius a . Assume
that the current is distributed uniformly over any circular cross section of the cone, so that
the current density does not depend on radial position. (The current density does vary
with position along the axis of the cone.) Show that the resistance between the two ends is
described by the expression: R= (density/pi)*(h/ab)
 
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welcome to pf!

hey jimmy! welcome to pf! :smile:

(have a pi: π :wink:)

pretend the cone is a series of very thin discs of height dh :wink:
 
alright thanks! i'll try that
 

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