Coupled Oscillator: Solving Initial Forces & Finding Eigenvalues

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SUMMARY

The discussion focuses on solving the initial forces and finding eigenvalues for a coupled oscillator system involving two masses, m_1 and m_2, connected by springs with constants k_1, k_2, and k_3. The participant formulates the forces acting on each mass, leading to a matrix representation of the system. However, the initial formulation results in imaginary angular frequencies, indicating a need for correction in the force equations. The final suggested equations for the forces are F_1 = -k_1x_1 - k_2x_1 + k_2x_2 and F_2 = -k_3x_2 + k_2x_1 - k_2x_2.

PREREQUISITES
  • Understanding of classical mechanics, specifically oscillatory motion.
  • Familiarity with matrix algebra and eigenvalue problems.
  • Knowledge of spring constants and their role in coupled oscillators.
  • Ability to formulate and solve differential equations related to mechanical systems.
NEXT STEPS
  • Study the derivation of eigenvalues for coupled oscillators using matrix methods.
  • Explore the implications of imaginary angular frequencies in mechanical systems.
  • Learn about normal modes and their significance in oscillatory systems.
  • Investigate the effects of varying spring constants on the stability of the system.
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Students and professionals in physics and engineering, particularly those focusing on mechanical vibrations, coupled oscillators, and system dynamics.

alex3
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Homework Statement


Two masses attached via springs (see picture attachment). k_n represents the spring constant of the n^{th} spring, x_n represents the displacement from the natural length of the spring.

There are two masses, m_1 and m_2.2. The attempt at a solution

My problem is formulating the initial forces on these. Here's what I've tried (with reference to the attached picture):

Mass m_1 has a force

F_1 = -k_1 x_1 + k_2 x_2

acting on it. We take right as the positive x direction, so mass 1 has the tension in spring 1 acting on it to the left, as well as the tension of spring 2 acting to the right.

Mass m_2 has a force

F_2 = -k_2 x_2 - k_3 x_3 = -x_2 (k_2 + k_3) - x_1 k_3

acting on it; spring 2 acts to the left (it's trying to contract), and spring 3, the longest spring, also acts to the left. Here is the assumption I'm unsure about, that the displacement of spring 3, x_3, is equal to the sum of the other two springs. I know I'll need to express x_3 in terms of x_1, x_2 as these correspond to the displacements of the masses, but this solution doesn't work.

3. Solving the equations

I'm OK with this part, I'm using matrix algebra to find the normal modes of the system (the eigenvalues). However, using the above logic I would end up with imaginary angular frequencies:

<br /> \[ \left(<br /> \begin{array}{cc}<br /> m_1 &amp; 0\\<br /> 0 &amp; m_2<br /> \end{array}<br /> \right)<br /> \left(<br /> \begin{array}{c}<br /> \ddot{x_1}\\<br /> \ddot{x_2}<br /> \end{array}<br /> \right)<br /> =<br /> \left(<br /> \begin{array}{cc}<br /> k_1 &amp; -k_2\\<br /> k_3 &amp; k_2 + k_3<br /> \end{array}<br /> \right)<br /> \left(<br /> \begin{array}{c}<br /> x_1\\<br /> x_2<br /> \end{array}<br /> \right)\]<br />

Eventually giving:

<br /> \[ \left|<br /> \begin{array}{cc}<br /> \frac{k_{1}}{m_{1}}-\omega^{2} &amp; -\frac{k_{2}}{m_{1}}\\<br /> \frac{k_{3}}{m_{2}} &amp; \frac{k_{2}+k_{3}}{m_{2}} - \omega^{2}<br /> \end{array}<br /> \right|\]<br />

And the solutions to the quadratic in \omega^{2} that this produces has imaginary roots, which is not ideal!

So; which initial formulation will help me?
 

Attachments

  • coupled-oscillators-diagram.jpg
    coupled-oscillators-diagram.jpg
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Solution:

F_{1} = -k_{1}x_{1} - k_{2}x_{1} + k_{2}x_{2}
F_{2} = -k_{3}x_{2} + k_{2}x_{1} - k_{2}x_{2}

Thanks all the same!
 

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