Covariant Derivative Commutation

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SUMMARY

The general formula for commuting covariant derivatives of a (r,s)-tensor field is established as follows: for a vector field \( U^{\gamma} \), the expression is given by \( (\nabla_{\alpha} \nabla_{\beta} - \nabla_{\beta} \nabla_{\alpha}) U^{\gamma} = R^{\gamma}_{\delta \alpha \beta} U^{\delta} \). A discrepancy in sign between this formula and an alternative source is attributed to differing conventions for the Riemann tensor. For non-coordinate bases, the Riemann tensor can be computed using connection coefficients as outlined in "Gravitation" by Misner, Thorne, and Wheeler (MTW), specifically on page 210, formula 8.24b.

PREREQUISITES
  • Understanding of covariant derivatives
  • Familiarity with Riemann curvature tensor
  • Knowledge of tensor fields
  • Basic concepts of differential geometry
NEXT STEPS
  • Study the Riemann tensor sign conventions in differential geometry
  • Explore the implications of covariant derivatives in non-coordinate bases
  • Review Misner, Thorne, and Wheeler's "Gravitation" for detailed examples
  • Learn about the properties of (r,s)-tensor fields in various contexts
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Mathematicians, physicists, and students of differential geometry seeking to deepen their understanding of covariant derivatives and Riemann curvature in both coordinate and non-coordinate frameworks.

PLuz
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Hello,

Can anyone tell me the general formula for commuting covariant derivatives, I mean, given a (r,s)-tensor field what is the formula to commute covariant derivatives?

I found a formula http://pt.scribd.com/doc/25834757/21/Commuting-covariant-derivatives page 25, Eq.6.18 but it doesn't seem right, since for a vector field one would write:

(\nabla_{\alpha} \nabla_{\beta}- \nabla_{\beta}\nabla_{\alpha})U^{\gamma}=R^{\gamma}\hspace{.5 mm}_{\delta \alpha \beta}U^{\delta}

And according to the formula in the link it would be, for a vector field(\nabla_{\alpha} \nabla_{\beta}- \nabla_{\beta}\nabla_{\alpha})U^{\gamma}=-R^{\gamma}\hspace{.5 mm}_{\delta \alpha \beta}U^{\delta}

Thank you
 
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I see only a difference in minus signs between the two expressions which can be accounted for in the convention used to define the Riemann tensor. I believe this formula is correct (at least for a coordinate basis, I cannot be sure if there are more terms for a non-coordinate basis).
 
For non-coordinate (aka anholonomic) basis, compute the Riemann tensor (it doesn't matter which sign convention you use) with the connection coefficients as provided in MTW page 210, formula 8.24b.
 

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