Covariant derivative in coordinate basis

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SUMMARY

The discussion focuses on evaluating the covariant derivative ##\nabla_{\mu} A^{\mu}## in a coordinate basis, demonstrating that ##\nabla_{\mu} A^{\mu} = \frac{1}{\sqrt{|g|}} \partial_{\mu} (|g|^{1/2} A^{\mu})##. The derivation involves manipulating terms of the Christoffel symbols, specifically showing that the first and third terms cancel out. The user expresses confusion regarding the assumptions made that limit the result to coordinate bases and seeks clarification on the generality of the expression and the most general form of the Christoffel symbols.

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  • Basic concepts of tensor calculus
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LCSphysicist
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I need to evaluate ##\nabla_{\mu} A^{\mu}## at coordinate basis. Indeed, i should prove that ##\nabla_{\mu} A^{\mu} = \frac{1}{\sqrt(|g|)}\partial_{\mu}(|g|^{1/2} A^{\mu})##.

So, $$\nabla_{\mu} A^{\mu} = \partial_{\mu} A^{\mu} + A^{\beta} \Gamma^{\mu}_{\beta \mu}$$

The first and third terms of Christoffel will cancel, so $$ = \partial_{\mu}A^{\mu} + A^{\beta} \frac{g^{\mu x}}{2}(\partial_{\beta}g_{x \mu})$$

Now, using the fact that ##\delta g = g g^{\mu v} \delta g_{\mu v}##, we can easily find that $$\frac{g^{\mu x}}{2}(\partial_{\beta}g_{x \mu}) = \frac{\partial_{\beta}(|g|^{1/2})}{|g|^{1/2}}$$

After substitute this at our main expression, we can recover ##\nabla_{\mu} A^{\mu} = \frac{1}{\sqrt(|g|)}\partial_{\mu}(|g|^{1/2} A^{\mu})##.

The problem is, i have no idea what assumption i have made so that my result applies only to coordinate basis! That is, the problem ask for prove it at coordinate basis , so i guess it should be true only at these type of basis. But i haven't assumed nothing, just manipulate the terms and got the result. What am i missing? Is this expression really general like i have found?
 
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You have used the coordinate expression for the Christoffel symbols.
 
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Orodruin said:
You have used the coordinate expression for the Christoffel symbols.
I know there are another expressions for Christoffel symbol, like:
$$\Gamma^{i}_{jk} = - \partial e^{i}/\partial x^{j} e_{k}$$
But i didn't know that this expression i have used is not the most general. What is the most general expression for it so? (namely, the one that makes no reference to any frame)
 

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