Cracking an Egg: The 9.81N Mystery

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SUMMARY

The discussion centers on the physics of cracking an egg, specifically addressing the discrepancy between the commonly cited force of 25 Newtons required to crack an egg and the calculated force from a drop test. The user conducted a drop test from an 8-meter height, calculating the impact force as 9.81 Newtons based on the weight of a 1 kg box. Through further calculations, they deduced that an egg would need to weigh approximately 2.55 kg to require 25 Newtons to crack, which is not feasible. The conversation highlights the importance of considering height and momentum in understanding the forces involved in cracking an egg.

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  • Familiarity with the concepts of force, mass, and acceleration
  • Knowledge of momentum and its calculation (momentum = mass * velocity)
  • Experience with basic physics experiments, such as drop tests
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kimdesug
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I am confused that many web sites say that it took 25 N to crack the egg, it's ok but

When I do the drop test with 8 meter building. So, I calculate the force: 1kg(box) * 9.81m/s^2

So, the force tat impact my box is 9.81 Newton but the egg was crack. I just confuse!
 
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You dropped a box? Try dropping a single egg. How much does a single egg weigh? I never used them so take it 'x', w=mg
=9.8x
They say 25N no? well
25=9.8x
x=25/9.8
=2.55
an egg can't be 2.55 kg right?
At what height did they drop the egg?
momentum=mass*velocity.
when you drop the egg from great height, by the time it reaches the earth, the velocity increases much and hence momentum. And hence it experiences much force. U must consider the height.
 
Ty i get it
 

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