Crane Efficiency: 5.10 x 10^5 Energy to Lift 1000kg 32m

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Homework Help Overview

The discussion revolves around calculating the efficiency of a crane that uses a specified amount of energy to lift a mass to a certain height. The subject area includes concepts of energy, efficiency, and basic physics principles related to lifting objects.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to identify the correct formula for calculating efficiency but expresses confusion regarding the appropriate approach. Some participants provide hints regarding the energy required for lifting and the relationship between power and energy.

Discussion Status

Participants are actively discussing the definitions of energy and power, with some clarifying that the energy used can be applied to calculate efficiency. There is an ongoing exploration of the concepts without a clear consensus on the method to be used.

Contextual Notes

The original poster appears to be struggling with the application of formulas and the distinction between energy and power, indicating a potential gap in understanding the underlying physics concepts.

puregoodboi
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What is efficiency of a crane that uses 5.10 x 10 to the fifth power of energy to lift 1000kg a vertical height of 32.0 m ?

geez what formula do i use lol i tried using the heat energy formula but to no avail T_T someone offer help lol like what formula do i use?
 
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Hints:

How much energy is required to lift the mass to the required height?
Efficiency = power needed / power actually used
 
5.10 x 10 to the fifth power of energy would this be the power actually used?
 
Yes. Well, energy, not power, but you can use the energy to calculate the efficiency in this case. Technically, power is energy per unit time.
 

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