Crate being pulled with and without friction

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SUMMARY

The problem involves a 51.0 kg crate being pulled with a constant horizontal force of 250 N across a distance of 20.0 m, with the first 10.0 m on a frictionless surface and the next 10.0 m with a coefficient of friction of 0.20. The solution requires applying Newton's 2nd law to determine the acceleration during both segments. The final speed of the crate can be calculated by first finding the final velocity after the frictionless segment and then using that as the initial velocity for the segment with friction, ultimately leading to the final speed after 20.0 m.

PREREQUISITES
  • Understanding of Newton's 2nd law of motion
  • Familiarity with kinematic equations
  • Knowledge of friction and its coefficient
  • Ability to perform vector summation of forces
NEXT STEPS
  • Calculate acceleration using Newton's 2nd law for both segments
  • Apply kinematic equations to find final velocity after the first 10.0 m
  • Determine the frictional force using the coefficient of friction
  • Recalculate final velocity for the second segment incorporating friction
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Students studying physics, particularly those focusing on mechanics and dynamics, as well as educators looking for practical examples of force and motion concepts.

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Homework Statement



A 51.0 kg crate, starting from rest, is pulled across a floor with a constant horizontal force of 250 N. For the first 10.0 m the floor is frictionless, and for the next 10.0 m the coefficient of friction is 0.20.

What is the final speed of the crate after being pulled these 20.0 m?


The Attempt at a Solution


I'm just really not sure what to do or where to start on this problem. please help.thanks
 
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I'm not to sure about this but I think you can divide it into two parts first. Find the Vf of the first 10.0 m then use that as the Vi for the other 10.0 m with friction and find the Vf again. That should give you the answer I believe.
 
Last edited:
Use Newton's 2nd law and vector summation to find the acceleration of the crate for both parts. For the first part the net force is just 250n, and for the second part it is 250n - Friction. Then use kinematics.
 

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