1. The problem statement, all variables and given/known data 324,000 cubic feet of soil is to be placed in a rectangular area (constructed from hay bales) of 80 feet x 100 feet. Using a slope of 1:1 for the fill soil, how many bales high must the walls be stacked to accommodate the soil? Assume the hay bales have a height of 18" 2. Relevant equations A = L x W V = A x h Volume of a pyramid...? 1/3(L x W x h) = V 3. The attempt at a solution I started by calculating the required height (assuming the soil was filled without a slope): 324,000 cu ft = 8000ft x h h = 40.5 ft I know from here I would simply divide the total height (h) by the height of a hay bale (18"), to get the number of bails. However, I am thinking that my calculated height is too much, since the soil will be slopped (1:1 slop) and extend above the walls. My question is, how do I figure out how high the soil can be slopped above the walls? and what the volume of soil extending above the walls would be. I was thinking this may have something to do with calculating the volume of a pyramid... but I'm a bit confused as to how to proceed. Any help or suggestions would be greatly appreciated.