Creating an exponential equation

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SUMMARY

The discussion centers on calculating the doubling period of a bacteria culture that starts with 3000 bacteria and reaches 48,000 in 3 hours. The correct formula to use is based on the doubling time rather than half-life, leading to the conclusion that the doubling time is 3/4 hours. The initial attempt incorrectly applied the half-life formula, resulting in confusion over the negative sign in the calculation. Ultimately, the doubling occurs four times within the 3-hour period.

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Homework Statement



A bacteria culture starts with 3000 bacteria.
After 3 h, the estimated counting is 48 000. What is the doubling period?


The Attempt at a Solution


I figured it would look like the half-life formula, so I wrote it as:

B = B0(0.5)t/h
Then I subbed numbers in:
48 000 = 3000(0.5)3/h
16 = 3/h (log0.5)
h = 3 (log0.5/log16)
h = -0.75

The answer at the back was 3/4 h, but I don't know if I did it correctly. I don't think the (-) makes sense.
 
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Replace 0.5 with 2... i.e replace "half life" with "doubling".
 
Coto is exactly right. Note, by the way, that 48000 is 16 times 3000 so in 3 hours it has far more than doubled- the doubling time is less than 3 hours not more.

Which means, in fact, that you answer is correct- it has doubled 4 times in 3 hours. The doubling time is 3/4 hours. You have a negative sign because
\left(\frac{1}{2}\right)^{-1}= 2
 
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