Critical angle/ last angle of refraction

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Homework Help Overview

The discussion revolves around determining the critical angle for a piece of glass with a specified index of refraction and sketching the path of a light ray as it interacts with the glass. The problem involves concepts from optics, specifically Snell's law and the behavior of light at interfaces.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants question the lack of information regarding the incident angle of the light ray and the angle of the glass's slope. There are attempts to make assumptions about these angles to facilitate drawing the light path.

Discussion Status

The discussion is ongoing, with participants exploring various assumptions about the incident angle and the geometry of the glass. Some have suggested that assuming a normal incidence could simplify the problem, while others express uncertainty about how to proceed without more information.

Contextual Notes

There is a noted lack of specific details regarding the incident angle and the slope of the glass, which participants feel is crucial for solving the problem effectively.

davidelete
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Homework Statement


A piece of glass has the shape shown in the below diagram. The index of refraction of the glass is 1.45. Find the critical angle for the glass. Sketch the path of the light ray until it emerges from the side of the figure and find the last angle of refraction.

http://img179.imageshack.us/img179/6531/physicsimageez8.png
Sorry if the image is a little ugly...

Homework Equations


Snell's law

n_1\sin\theta_1 = n_2\sin\theta_2\ .


The Attempt at a Solution


sin-1(\frac{1}{1.45})=43.6 degrees.

I have no idea on how to draw in the diagram. Could someone help me on drawing it? Mine just looks like a bunch of rays bouncing around inside an irregular pentagon on my paper when I try it.
 
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Are we told the angle at which the light is incident on the glass? Is it incident normally (at 90 degrees)?
 
astrorob said:
Are we told the angle at which the light is incident on the glass? Is it incident normally (at 90 degrees)?

That is truly everything. I would just have to assume 90 degrees based on the information given.
 
I don't understand how you're expected to solve that without the incident angle and also the angle at which the glass is sloped on the left hand side.
 
I suppose it is more of a best guess type of thing. What would your best guess be when drawing a light beam coming in? Where would it bounce to? Where would it exit?
 
If you don't know what angle its entering the medium relative to the normal then how are you supposed to know if it will internally reflect? It could either exit the medium on the second face or bounce around inside for a while...

As a best guess, and this seems so entirely unphysical that it should have a disclaimer, i'd assume it enters the medium normally, and assume that the angle of the slope is 45 degrees. Since this is a larger angle than critical, it's going to bounce off the lower face, then off the top face, then off the right face, then off the bottom face, and then exit normally out the face it came in through.
 
astrorob said:
If you don't know what angle its entering the medium relative to the normal then how are you supposed to know if it will internally reflect? It could either exit the medium on the second face or bounce around inside for a while...

As a best guess, and this seems so entirely unphysical that it should have a disclaimer, i'd assume it enters the medium normally, and assume that the angle of the slope is 45 degrees. Since this is a larger angle than critical, it's going to bounce off the lower face, then off the top face, then off the right face, then off the bottom face, and then exit normally out the face it came in through.

Thank you. That was exactly what my best guess looked like as well. Some of the questions on these homeworks are outrageous. I wish they gave more information.
 

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