Critical points of matrix

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SUMMARY

The discussion centers on identifying critical points of the system defined by the equations x' = x - 2y and y' = -2x + 4y. The condition for critical points is established as x' = y' = 0, leading to the equations 0 = x - 2y and -2x + 4y = 0. The conclusion drawn is that the critical points are represented as (2y, y), indicating an infinite number of critical points due to the linear dependence of the equations. Participants emphasize the importance of verifying initial problem equations to avoid confusion.

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Homework Statement
Give their critical points of this system which can be written as a matrix:
##x^{\prime}=x - 2y, y^{\prime}=-2x+ 4y##
Relevant Equations
##x^{\prime}=x - 2y, y^{\prime}=-2x+ 4y##
My attempt is:

Condition for critical point is ##x' = y' = 0##,
##0 = x - 2y \implies 2y = x##
##-2x + dy = 0##
Then ##-4y + 4y = 0##

However, this means that critical points are ##(2y, y)## as system is linearly dependent (both equations are the same) where ##y \in \mathbb{R}##. However, that means there are infinitely many critical points which I have a doubt about.

I express gratitude to those who help.
 
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TanWu said:
However, that means there are infinitely many critical points which I have a doubt about.
Why so?
 
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TanWu said:
Homework Statement: Give their critical points of this system which can be written as a matrix:
##x^{\prime}=x - 2y, y^{\prime}=-2x+ 4y##
Relevant Equations: ##x^{\prime}=x - 2y, y^{\prime}=-2x+ 4y##

My attempt is:

Condition for critical point is ##x' = y' = 0##,
##0 = x - 2y \implies 2y = x##
##-2x + dy = 0##
Do you mean ##-2x + 4y = 0## here?
TanWu said:
Then ##-4y + 4y = 0##

However, this means that critical points are ##(2y, y)## as system is linearly dependent (both equations are the same) where ##y \in \mathbb{R}##. However, that means there are infinitely many critical points which I have a doubt about.
Your work looks ok to me. If you have doubts, have you checked that you got the initial problem equations right?
 
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docnet said:
Why so?
FactChecker said:
Do you mean ##-2x + 4y = 0## here?

Your work looks ok to me. If you have doubts, have you checked that you got the initial problem equations right?
Thank you Sirs. I apoglize, that is a typo of me. Yes, got the initial problem equations correct. I was only expecting one critical point.
 
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TanWu said:
Thank you Sirs. I apoglize, that is a typo of me.
Mathematics is very unforgiving in many ways. It's a learned skill to review your work very carefully.
TanWu said:
Yes, got the initial problem equations correct. I was only expecting one critical point.
You did a good job! The problems where you get a different answer than you expected are ones that really test you.
 
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