Critique my proof of the Arzela-Ascoli Theorem (with one question)

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The forum discussion critiques a proof of the Arzela-Ascoli Theorem, specifically addressing the importance of the finiteness of the set {r_1, r_2, ..., r_n}. The user raises concerns about demonstrating uniform convergence of the sequence g_k and the necessity of combining individual N_i into a single N, which relies on the finiteness of the set. Additionally, the critique points out inconsistencies in the proof regarding the selection of delta in part (c), highlighting the need for clarity in the proof structure.

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jdinatale
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In part (b), I'm not sure why it's important that r_1, r_2, ..., r_n is finite. Any thoughts? One thing I'm concerned about is if I have really shown that g_k converges uniformly because I did not shown that the N chosen was independent of the x.

arzela1.png


arzela2.png


arzela3.png
 
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The problem is of course that every [itex]r_i[/itex] gives rise to a different N.

That is: you know that [itex](g_s(r_i))_s[/itex] is Cauchy, thus we can write:

[tex]\forall \varepsilon >0:\exists N_i: \forall s,t>N_i:~|g_s(r_i)-g_t(r_i)|<\varepsilon[/tex]

I wrote [itex]N_i[/itex] here instead of [itex]N[/itex] because we do not have only one N.

Now you must combine the [itex]N_i[/itex] into one N. This will use finiteness.


A critique of your proof: you have not shown that we can actually choose a finite set [itex]\{r_1,...,r_n\}[/itex] that satisfies the criteria. This is very important and uses something essential.

Furthermore, your proof of (c) isn't quite nice. You say "we may choose [itex]\delta>0[/itex]", but you do realize that this delta was already chosen in (b)?
 

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