Cross product associative triples

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nikcs123
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cross product "associative triples"

Homework Statement



We know that the cross product is not associative, i.e., the identity
(1) [tex](\vec{a}\times\vec{b})\times\vec{c}[/tex] = [tex]\vec{a}\times(\vec{b}\times\vec{c})[/tex] is not true in general. However, certain special triples [tex]\vec{a}[/tex];[tex]\vec{b}[/tex];[tex]\vec{c}[/tex]
of vectors do satisfy (1). For example, if one of the vectors is the zero vector, then (1)
holds trivially, but there are also less obvious examples. Call a triple [tex]\vec{a}[/tex];[tex]\vec{b}[/tex];[tex]\vec{c}[/tex] for which (1)
holds "associative". Characterize all nonzero associative triples by some simple geometric
condition. (An example of a possible condition (though not the correct one) would be that
the three vectors are pairwise perpendicular.)

The Attempt at a Solution



I attempted to use the properties/identities of cross products to deduce a relationship between the components of each vector and try to piece it together that way, ended up with a huge mess and no progress... Just need a nudge in the right direction on this one.
 
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Did you try to use the triple product expansion formulas:

[tex]a\times(b\times c)=b(a,c)-c(a,b)[/tex]

[tex](a\times b)\times c=-c\times (a\times b)=c\times (b\times a)=...[/tex]
 


Thank you arkajad.

[tex](\vec{a}\times\vec{b})\times\vec{c}=\vec{a}\times(\vec{b}\times\vec{c})[/tex]

Working with the left side,

[tex](\vec{a}\times\vec{b})\times\vec{c}=-\vec{c}\times(\vec{a}\times\vec{b})=\vec{c}\times(\vec{b}\times\vec{a})[/tex]

So then

[tex]\vec{c}\times(\vec{b}\times\vec{a})=\vec{a}\times(\vec{b}\times\vec{c})[/tex]

For the above to be true, [tex]\vec{a}=\vec{c}[/tex]. Furthermore, the above also holds true when [tex]\vec{a}[/tex] and [tex]\vec{c}[/tex] are parallel.

That is correct, right?
 


nikcs123 said:
For the above to be true, [tex]\vec{a}=\vec{c}[/tex]. Furthermore, the above also holds true when [tex]\vec{a}[/tex] and [tex]\vec{c}[/tex] are parallel.

That is correct, right?

Why don't you bring in the equality involving scalar products and justify your conclusion? Perhaps you have missed something?