Cube balanced at equilibrium about two different axes

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A cube balanced on an edge with its center of gravity directly above is in unstable equilibrium regarding rotation about that edge and stable equilibrium concerning rotation about a horizontal axis perpendicular to the edge. The discussion clarifies that a modest torque applied about the perpendicular axis does not affect the cube's position, indicating stability. Participants explore the concept of unstable equilibrium, suggesting that if the cube were balanced on a point, it would be unstable across all horizontal axes. The conversation emphasizes understanding the conditions for stability and instability in different rotational scenarios. Overall, the analysis reinforces the principles of equilibrium in physics.
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Homework Statement


A cube balanced with one edge in contact with a table top and with its center of gravity directly above the edge is in _______ equilibrium with respect to rotation about the edge and in _________ equilibrium with respect to rotation about a horizontal axis that is perpendicular to the edge.

A. stable, stable
B. stable, unstable
C. unstable, stable
D. unstable, unstable
E. unstable, neutral

Homework Equations


The Attempt at a Solution


I know the answer is C.

So it's clear to me that the first one is unstable.

And maybe I'm overthinking this but for the second option, I can't seem to put in my head why it's stable. Do we just imagine that it's fixed on its edge and rotating about the horizontal axis?

And more importantly, what would it look like for the cube to be in unstable equilibrium relative to the horizontal axis.
 
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eprparadox said:
Do we just imagine that it's fixed on its edge and rotating about the horizontal axis?
Both axes are horizontal. Do you mean the perpendicular axis?
It is stable about the perpendicular axis because a modest torque applied about such an axis will have no affect.
eprparadox said:
what would it look like for the cube to be in unstable equilibrium relative to the horizontal axis.
Unstable about all horizontal axes? Balanced on a point.
 
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Awesome, this makes a lot of sense. Thanks so much
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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