Cubic Equation Roots: Solving for α and β | p Value Calculation

  • Thread starter Thread starter ibysaiyan
  • Start date Start date
  • Tags Tags
    Cubic Roots
Click For Summary

Homework Help Overview

The discussion revolves around solving a cubic equation of the form x³ - 3x² + px + 4 = 0, where the roots are expressed in terms of α and β. Participants are tasked with finding the values of α and β, as well as the constant p, given the specific structure of the roots.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss using the relationships between the coefficients of the polynomial and the roots, specifically referencing the sum and product of the roots. There is an exploration of how to express the roots in terms of α and β, and how to derive the necessary equations from these relationships.

Discussion Status

The conversation is ongoing, with participants sharing their thoughts on how to apply the relationships between the roots and coefficients. Some have suggested methods for finding α and β, while others are questioning their interpretations and calculations. There is a collaborative effort to clarify the steps needed to progress.

Contextual Notes

Participants are navigating through the constraints of the problem, including the requirement that β is greater than 0 and the specific form of the roots. There is also a mention of potential confusion regarding the presentation of their reasoning and calculations.

ibysaiyan
Messages
441
Reaction score
0

Homework Statement


The equation
x3 − 3x2 + px + 4 = 0,
where p is a constant, has roots α −β , α and α + β , where β > 0.
(a) Find the values of α and β .
(b) Find the value of p.
how do i start off? all i know is that sigma a= -b/a and ab= c/a and ab(gamma) = -d/a .
Would this be one of the ways to do it: [x-(a-β)] [x-(a+β)] (x-a).
Thanks.


Homework Equations





The Attempt at a Solution

 
Physics news on Phys.org
You know that ∑α=-b/a, so use that to find α. ∑αβ=c/a and ∑αβγ=-d/a.

So start off using the first method. Sum of all of the roots and equate it to 3. Do a similar exercise for the product of the roots.
 
rock.freak667 said:
You know that ∑α=-b/a, so use that to find α. ∑αβ=c/a and ∑αβγ=-d/a.

So start off using the first method. Sum of all of the roots and equate it to 3. Do a similar exercise for the product of the roots.

Oo is this how it works: ∑α=-b/a => -(-3)/1 = 3.
to find b: ∑ab=c/a
= ∑a.∑b= c/a.
3∑b=px ... b=px/3. <--- sorry for such a weird presentation. Not sure :(.
 
ibysaiyan said:
Oo is this how it works: ∑α=-b/a => -(-3)/1 = 3.
to find b: ∑ab=c/a
= ∑a.∑b= c/a.
3∑b=px ... b=px/3. <--- sorry for such a weird presentation. Not sure :(.

Yes, but ∑α is the sum of the roots, your roots are α−β , α and α + β, what are the sum of the roots?
 
rock.freak667 said:
Yes, but ∑α is the sum of the roots, your roots are α−β , α and α + β, what are the sum of the roots?

3a?:confused:
 
ibysaiyan said:
3a?:confused:

Right yes good 3α.

So ∑α=3α=3, what is α then?
 
rock.freak667 said:
Right yes good 3α.

So ∑α=3α=3, what is α then?

Oh! its one.. so to find out constant b would i mutiply out my roots:when a=1
(1-b) (1+b) (1) = i think its wrong =/ .
 
Another way to do this would be to set
(x- \alpha- \beta)(x- \alpha)(x- \alpha+ \beta)= x^2- 3x^2+ px+ 4
multiply it out and set corresponding coefficients equal. That gives you three equations for \alpha, \beta, and p.
 

Similar threads

Replies
31
Views
4K
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
2K
Replies
1
Views
2K
Replies
11
Views
7K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K