Current Across Diode for DC Sources: 0.86mA

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SUMMARY

The discussion centers on calculating the current across a diode in a circuit with two voltage sources: 30V and 10V. The calculated current across the diode is 0.86mA, derived from applying Ohm's Law (V=IR) and considering the diode's forward bias voltage drop of 0.7V. Participants clarify the need to analyze the circuit by splitting it into two parts, one for each voltage source, and utilizing Thevenin equivalents to simplify the calculations. The correct approach involves determining the current through each resistor and then deducing the diode's current from the difference.

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  • Understanding of Ohm's Law (V=IR)
  • Knowledge of diode characteristics, specifically forward bias and voltage drop
  • Familiarity with Thevenin's theorem for circuit analysis
  • Basic circuit analysis skills, including current and voltage calculations
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  • Learn about diode characteristics and their impact on circuit behavior
  • Practice solving diode circuit problems using Ohm's Law
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Electrical engineering students, circuit designers, and anyone involved in analyzing and designing diode circuits.

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Homework Statement

:Find the current that go across the diode ans=0.86mA[/B]
zvZG2.png


Homework Equations


V=IR

3. The Attempt at a Solution
The Vt(v total) is 30v
so,must i ignore the diode as off first?.In that case the current is 30/20=1.5 mA.
i also know the that diode is foward bias because 20v>10V
i know that the voltage drop for this diode is 0.7
(20-0.7)/10=1.93,this step is correct.
but i really need help for this qn
mods pls don't delete.. :)
 
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(20-0.7)/10=1.93,this step is correct.
That is the current for the 20V source. Also determine the current for the 10V source.
 
NascentOxygen said:
That is the current for the 20V source. Also determine the current for the 10V source.

hey but how can i just split the circuit into two?? lol, isist that weird?? like i used to learn that i should find the current and so on...
 
You have made the assumption that the diode is conducting...which means you are saying its cathode must be at a potential of -0.7V.

So with this assumption, you can then determine the current in each resistor.
 
http://imgur.com/l40uOZ2
http://imgur.com/l40uOZ2
the red arrow shows the current flow from the 10v source.No current from the 10V pass am I right??
 
What does Ohm's Law tell you for the resistor on the left, given your assumption that the diode's cathode is being held at -0.7V?
 
hey that's is the part i don't understand.. i really don't :(
 
nathanxx6969 said:
hey that's is the part i don't understand.. i really don't :(
You have a resistor, you know how many ohms, and you also know the voltage at either end of it ...
 
but shouldn't it be like (30-0.7 )/20?
 
  • #10
nathanxx, why don't you make things simpler for yourself? ... If you are studying diode circuits you very likely have already covered Thevenin equivalents. If you consider the diode as the load of the network, what would be the Thevenin equivalent of the circuit that is driving that load?

upload_2016-5-2_15-58-30.png
 
  • #11
nathanxx6969 said:
but shouldn't it be like (30-0.7 )/20?
The current in each resistor will be what Ohm's Law says it is. [emoji102]

⏩ From their difference you can deduce how much current must be going through the diode.
 

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