Current in superconductors when a voltage is applied.

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Discussion Overview

The discussion revolves around the behavior of current in superconductors when a voltage is applied, specifically in the context of a superconducting loop connected to a battery. Participants explore the implications of superconductivity on current flow, resistance, and the limitations imposed by the battery's internal resistance.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • One participant questions the application of Ohm's law (V = IR) to superconductors, suggesting that it leads to an infinite current due to zero resistance.
  • Another participant asserts that the current will be limited by the internal resistance of the battery, applicable to all batteries with low impedance loads.
  • A participant proposes calculating the current through the superconductor using the internal resistance of the battery, suggesting a value of 1.5Ω.
  • One participant states that the current can be calculated as I = V/R, claiming a resulting current of 9A due to the superconductor's zero resistance.
  • Another participant points out an arithmetic error in the previous calculation, later correcting it to 6A.
  • It is noted that superconductors can only carry currents below a critical value, beyond which they revert to normal conductivity.
  • A participant describes the scenario as analogous to an "irresistible force and immovable object" problem, emphasizing the complications of non-ideal conditions.

Areas of Agreement / Disagreement

Participants express differing views on the application of Ohm's law to superconductors and the role of the battery's internal resistance. There is no consensus on the correct approach to calculating the current in this scenario, and the discussion remains unresolved.

Contextual Notes

Limitations include assumptions about ideal conditions versus non-ideal behavior, as well as the dependence on the internal resistance of the battery, which is not universally defined in the discussion.

JackA7X
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Suppose you a have superconducting loop connected to a 9V battery. What is the current through it? With a resistance of 0Ω, V = IR gives ∞. I don't think that can be right... If it were, V=\frac{I}{nAe} would give an infinite velocity... Does that equation even apply to superconductors?
 
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Current will be limited by the internal resistance of the battery. This happens for all batteries connected to low impedance loads.
 
So if we assume the internal resistance is 1.5Ω how do you calculate the current through the superconductor?
 
I=V/R, just like always. In this case, 9A since a superconductor has 0 resistance.
 
Marcus
There seems to be an arithmetical error here.
 
Superconductors can only carry currents lower than a critical current value. If the current rises above that limit, they become normal conducting.
 
syhprum said:
Marcus
There seems to be an arithmetical error here.
Quite so, I hit the wrong key on my Blackberry. 6A.
 
Thank you, very helpful.
 
This is a "irresistible force and immovable object" type of question, if you don't allow something to be non-ideal.
 

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