1. The problem statement, all variables and given/known data A closed wire loop in the form of a square of side 4 cm is placed with its plane perpendicular to a uniform magnetic field, which is increasing at the rate of 0.3 T s-1. The loop has negligible inductance, and a resistance of 2 * 10-3 Ω. Calculate the current induced in the loop, and explain with the aid of a clear diagram the relation between the diraction of the induced current and the direction of the magnetic field. Answer: 0.24 A. 2. The attempt at a solution Well, I used the E = B L v and I = V / R formulas. E = 0.3 * (4 / 100) = 0.012 V. I = 0.012 / (2 * 10-3) = 6 A. What's wrong here?