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Current induced in the loop

  1. Oct 16, 2016 #1
    1. The problem statement, all variables and given/known data
    A closed wire loop in the form of a square of side 4 cm is placed with its plane perpendicular to a uniform magnetic field, which is increasing at the rate of 0.3 T s-1. The loop has negligible inductance, and a resistance of 2 * 10-3 Ω. Calculate the current induced in the loop, and explain with the aid of a clear diagram the relation between the diraction of the induced current and the direction of the magnetic field.

    Answer: 0.24 A.

    2. The attempt at a solution
    Well, I used the E = B L v and I = V / R formulas.

    E = 0.3 * (4 / 100) = 0.012 V.

    I = 0.012 / (2 * 10-3) = 6 A.

    What's wrong here?
     
  2. jcsd
  3. Oct 16, 2016 #2
    Hi!

    Here's a hint -
    Does this formula seem to apply here? Could you please list the value of each of these variables?
     
  4. Oct 17, 2016 #3
    Hi!

    E = voltage, B = magnetic field, L = length, v = velocity.

    If know that this formula is not the best fit for this problem (we don't know velocity). But which one do you suggest?
     
  5. Oct 17, 2016 #4
    Do you know Faraday's law of induction?
     
  6. Oct 17, 2016 #5
    Got it from here. Thank you!

    E = - N (d Φ / d t)

    d Φ / d t = 0.3 T s-1 * A, where A = (4 / 100) * (4 / 100) = 1.6 * 10-3 m2.

    E= - 1 * 0.3 * 1.6 * 10-3 = - 4.8 * 10-4 V.

    I = V / R = 4.8 * 10-4 / 2 * 10-3 = 0.24 A.
     
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