What Determines the Direction of Rotation in a Current Loop?

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The discussion centers on determining the rotation direction of a rectangular wire loop in a magnetic field created by a vertical wire carrying a current. A constant upward current in the wire and a clockwise current in the loop lead to confusion about the resulting forces on the loop's sides. The magnetic field is stronger on the side of the loop closer to the wire, affecting the forces acting on each side. Ultimately, the forces do not cause the loop to rotate out of its plane, leading to the conclusion that the loop does not rotate. Understanding the direction and strength of these forces is crucial for determining the loop's behavior in the magnetic field.
syhpui2
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Homework Statement



Consider a long wire running in the vertical direction with a rectangular loop of wire beside it as shown. Now suppose that a constant current, I, flows upward along the long wire, and the same magnitude current, I, flows clockwise in the loop.

As viewed from the top of the page, in which direction does the loop rotate?

(a) clockwise
(b) counterclockwise
(c) The loop does not rotate.


Answer:C

n6Vbw.png


http://i.imgur.com/n6Vbw.png

Homework Equations



F=BIXL

The Attempt at a Solution



I tried use RHR with loop. However, I get answer B because force points to right...
 
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With the current running toward the top of the diagram, which way do its magnetic field lines intersect the sides of the rectangular loop? We know the magnetic field is stronger on the side of the loop closer to the wire, BUT which way does the magnetic force act on the current in each of the four sides of the loop? The important question is: do these forces on the sides of the loop act in a way that will turn the loop out of the plane it is presently lying in?
 
dynamicsolo said:
With the current running toward the top of the diagram, which way do its magnetic field lines intersect the sides of the rectangular loop? We know the magnetic field is stronger on the side of the loop closer to the wire, BUT which way does the magnetic force act on the current in each of the four sides of the loop? The important question is: do these forces on the sides of the loop act in a way that will turn the loop out of the plane it is presently lying in?

do these forces on the sides of the loop act in a way that will turn the loop out of the plane it is presently lying in?

i thought the force on left edge is stronger because it is closer so it would rotate clockwise?
 
syhpui2 said:
i thought the force on left edge is stronger because it is closer so it would rotate clockwise?

To decide whether any rotation will occur, you need to figure out the direction of the forces acting on all four sides. The strength of the forces alone don't decide that question.
 
dynamicsolo said:
To decide whether any rotation will occur, you need to figure out the direction of the forces acting on all four sides. The strength of the forces alone don't decide that question.

Okay. That makes sense.
Thanks
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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