Current on a spring to withstand a weight.

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Homework Help Overview

The problem involves a spring modeled as a solenoid, where the objective is to determine the current required to support a mass without altering the spring's length. The discussion centers around the relationship between magnetic forces and gravitational forces in this context.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic energy and forces, questioning the notation used for variables and the differentiation process. There is an exploration of whether the derivative should be taken with respect to length and how to equate forces.

Discussion Status

The discussion is active, with participants providing feedback on the original poster's approach and seeking clarification on the notation and differentiation. There is a focus on ensuring that the energy considerations are correctly applied to the problem.

Contextual Notes

There is some confusion regarding the notation of variables and the differentiation process, which may impact the interpretation of the problem. Participants are also considering the implications of length changes on the energy of the system.

pitbull
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Homework Statement


You have a spring of length l, radius R, with N loops and n loops per unit length. If you consider it a solenoid, what current do you need to apply to withstand a mass m hanging from it, without stretching or shrinking the spring.

Homework Equations


Magnetic field inside a solenoid: B0nIz
Magnetic energy: W=∫∫∫B2/(2μ0)dV

The Attempt at a Solution


I calculated the magnetic energy of a solenoid and I got:
W=μ0N2I2πR2/(2l)

The force applied by the mass is:
F=mg

So, the magnetic force that I need is:
F=∇W(length constant)=μ0N2IπR2/(l)

Both forces must be equal. I solve for I and I get:
I=mgl/(μ0N2πR2)

Do you thing it is right?
 
Last edited:
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The approach looks good, but I get confused by the notation with I, l and l.
The derivative has to be with respect to length.
 
mfb said:
The approach looks good, but I get confused by the notation with I, l and l.
The derivative has to be with respect to length.

So should I derivate with respect to length and then equal that derivative to mg?
 
Sure. You are interested in the total energy after a length change to see if this length change happens.
 
mfb said:
Sure. You are interested in the total energy after a length change to see if this length change happens.

And after equaling both quantities, I solve for I (current), right?
 
Sure.
 
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