Current, Resistivity, and strange questions

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SUMMARY

The discussion focuses on deriving expressions for current density and electric field in a thin aluminum film influenced by a copper ring and disk configuration. The key parameters include the current I, radii a and b, thickness t of the film (1 µm), and resistivity ρ. The current density J is defined as J = I/A, and the relationship between current density and electric field is established as E = ρJ. The resistance between the disk and ring is evaluated with specific values: b = 10 mm and a = 5 mm.

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Homework Statement


A sheet of aluminum is 1 um thick. A thick copper ring of radius b is placed on the film, and a (smaller) copper disk, of radius a, is placed on the film at the centre of the ring. The disk and ring are connected to the terminals of a battery, so that current I flows through the film from the ring to the disk. Derive, in terms of I, a, b, and the thickness t and resistivity \rho of the film, expression for the current density and electric field in the film as functions of the distance r from the centre of the disk and ring. Evaluate the resistance between the disk and ring if b = 10 mm, a = 5mm, t = 1 um.

Homework Equations


current density J is defined as J \equiv \frac{I}{A}
current density related to the electric field: J = \sigma E
since \sigma = \frac{1}{\rho} therefore E = \rho J

The Attempt at a Solution


The further out away from the centre, the lower the current density will be, since there will be the same amount of charge flowing over a greater area.

I'm can't think of a way that needs a, b, or thickness. I don't know how the copper is affecting the current, since current is given. All I can think of right now is
J(r) = \frac{I}{2 \pi r^{2}}
and then E(r) = \frac{\rho I}{2 \pi r^{2}}
Thanks~
 
Last edited:
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Are you giving the whole problem? What is b?

Edit: My mistake. Sorry.
 

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