Current Through A Resistor That Is In Parallel With A Capacitor

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The discussion focuses on calculating the current through a resistor in parallel with a capacitor using Kirchhoff's Voltage Law. The main challenge is determining the appropriate resistance (R) for the time constant (tau), which is believed to be independent of the parallel resistor's resistance. The time constant is defined as the time taken for the capacitor to charge to approximately 60%, with an initial assumption that tau equals 50 times the capacitance. The conversation suggests that using Thevenin's Theorem could simplify the analysis, although it is not part of the current curriculum. Ultimately, understanding Thevenin's method may enhance circuit analysis skills for more complex problems.
solour
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Homework Statement


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My question is regarding part C of the question.

Homework Equations


V = IR
V(t) = V(1-e^(-t/tau))

The Attempt at a Solution


My idea is to use Kirchoff's Voltage Law and find the voltage of the capacitor as a function of time, then since the voltage across capacitor is the same as voltage across resistor I can simply divide that by a constant R and obtain current as a function of time.

The problem I am running into is: I am unsure what to put as R in the time constant.
To my understanding time constant is the amount of time it takes to charge the capacitor to about 60%, and from my instinct it does not depend on the resistance of light bulb that is in parallel with the capacitor. Therefore Tau(time constant) = 50*Capacitance.

However, I am unsure of what I said above, and would like to know if there's a more definitive way to find the R value for time constant. I did see one approach which uses Thevenin's Equivalence but it was very confusing.
 
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Thevenin is the way.

Show what you've tried and where it gets confusing.
 
solour said:

Homework Statement


http://imgur.com/a/KnYI2
http://imgur.com/a/KnYI2
My question is regarding part C of the question.

Homework Equations


V = IR
V(t) = V(1-e^(-t/tau)

The Attempt at a Solution


My idea is to use Kirchoff's Voltage Law and find the voltage of the capacitor as a function of time, then since the voltage across capacitor is the same as voltage across resistor I can simply divide that by a constant R and obtain current as a function of time.

The problem I am running into is: I am unsure what to put as R in the time constant.
To my understanding time constant is the amount of time it takes to charge the capacitor to about 60%, and from my instinct it does not depend on the resistance of light bulb that is in parallel with the capacitor. Therefore Tau(time constant) = 50*Capacitance.
gneill said:
Thevenin is the way.

Show what you've tried and where it gets confusing.
I am taking first year physics and Thevenin is not in the curriculum so I'm not sure how to calculate it. I will learn how it works then!
 
solour said:
I am taking first year physics and Thevenin is not in the curriculum so I'm not sure how to calculate it. I will learn how it works then!
Okay. After you've done some research come back with any questions.
 
solour said:
I am taking first year physics and Thevenin is not in the curriculum so I'm not sure how to calculate it. I will learn how it works then!
Thevenin would be the easiest and most practical way of doing this problem. But if it is not in your curriculum, I am not sure if you'll get full credit for this question if it is a part of your assignment or exam. After solving this problem using Thevenin, you might want to try the usual mesh analysis KVL method.

But the Thevenin method will surely be very useful for you to analyse circuits with increased complexity.
 
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