let's try this train of thought.
It's hard to swap our mind from a voltage transformer to a current transformer.
Here's the concept
Voltage Transformer:
Voltage determines flux, even though current is what makes flux.
That's because while mmf = amp-turns
voltage = ndΦ/dt , Faraday
so flux Φ = 1/n X ∫voltage
and integral of sine is cosine...
That derivative-integral relationship is important.
Flux is measured in Webers or Maxwells
but volts per turn (at a known frequency) works just as well.
One weber per second induces one volt in one turn
so volts per turn is webers per second
Anyhow to keep it math-less,
applying a fixed voltage
to an inductor locks the flux at a level that'll make equal counter-emf.
There's some current level that'll make that amount of flux, and let's call that the "magnetizing current".
The more the inductance the less the magnetizing current.
If i add a second winding to that inductor i have made a transformer.
A good transformer will have lots of inductance so as to not waste too much current magnetizing the core.
Magnetizing current is 90 degrees (well around ninety) out of phase with applied voltage because it's inductive, and that derivative-integral relation holds.
If i now allow current to flow in secondary, that current immediately produces mmf that opposes primary mmf.
Immediately ? Yes, immediately because mmf is amp turns with no derivative-integral relationship.
Aha - secondary amp0turns must be immediately overcome(?)corrected(?)(choose a verb) by primary amp-turns,, else flux would drop and counter emf wouldn't balance applied voltage.
So - secondary current(let's call it load curent) is reflected into primary with no delay, and
no delay=no phase shift.
So - load current is not in phase with magnetizing current.
Primary current will be sum of magnetizing and load current phasors.
Sum of primary and secondary mmf's will produce mmf equal to magnetizing current mmf, because voltage is fixed.
In your original post you were thinking of secondary current being out of phase with primary magnetizing current, which it is,
but load current in secondar windings is in phase with load current reflected into primary. (i hope that wording is okay)
So - in a voltage transformer, primary mmf will be
whatever is necessary to support counter-emf.
Sum of mmf's is constant , and is substantial. Power transformers operate high up the B-H curve, near the knee.
http://commons.wikimedia.org/wiki/File:B-H_Curve.jpg
Now to the humble current transformer.
Hollow refers to the donut shaped core, which is
not a hollow circular shell .
The current transformer is an inductor as was the voltage transformer.
Since it goes in series with whatever device for whgich we wish to measure the current,
it is desirable to have low voltage across the CT so as to not impede current to our device.
That's true for any ammeter. How can i determine my awshing machine's current if the CT blocks current?
So we must keep flux in our CT as low as possible so it won't make any counter EMF.
Well that's easy, just short circuit the secondary.
Since the secondary mmf will cancel the primary mmf there'll be no flux to oppose primary current.
Why doesn't current rush in like in a voltage transformer, to restore flux? Because primary current is fixed by the circuit we're measuring.
Okay, that's cool.
What about phase?
Remember from the voltage transformer that mmf's cancel immediately with no phase shift...
So the secondary current ought to be in phase with primary current, since it's all "load current".
Okay, but as you said there's got to be some magnetizing current in the CT else it couldn't make secondary current.
Quite so.
How much magnetizing current?
Well,
system is ignoring preview and upload and post buttons again and I'm about to smash the screen
will be abck when things work better