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## Homework Statement

Using conductivity constant (q=1.45*10^6mA) deduce the cross-Sectional area of the wire from the slope of the Data found in the graph.

Voltage was kept constant 1.00 volts

The wires are each 1m long

After graphing the data the

Current(mA) # of parralel lines

121.4 1

268.8 2

442.2 3

578 4

The equation of the graph is

**y=.0065x+.2197**

## Homework Equations

**I=qVA/(L)**--------- I is current, q is conductivity constant=1/resistivity(p), V is voltage, A is cross sectional area, L is length of the wire.

**R=pL/A**

**R=V/I**

## The Attempt at a Solution

I was thinking that since the number of wires are increasing and the voltage is constant the resistance is dropping.

I'm not sure what the slope is representing and how i can put it to use in the formulas above.

If someone could please explain. Please let me know if you need any more information.