Thundagere
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Allright, an update. I ran through the equations during some free time today, this is what I came up with.
Q = mc∆T
m= 1000 grams (slightly more than a quart)
c = 3.98 (in the polluted water that I am handling, since I'm distilling it).
∆T = 75 degrees C, because from 100 degrees celsius to 25 degrees (room temp), is 75 degrees.
Keep in mind, I'm not bothering about heat of vaporization here, I'm just raising it to that temperature and then adding a couple of arbitrary minutes.
Q = 298500
Insolation of sun =1000 W / m^2
1 inch mirror tile = 6.45 cm ^2 = 6.45 * 10^4 m^2
Solar energy in a one inch mirror tile = 0.645 W (found by proportions).
Thus, 289000 = 0.645 J/s (time) (number of mirror tiles)
462790.697 = (time) ( number of mirror tiles)
Now, I put in 500 mirror tiles. I'll probably linear program it later (Never mind, I did linear program it, got about 500, give or take. I can't rely on my mental linear programming :) ) That leaves me with 925.5 seconds, or about 15 minutes. That isn't bad, all things considered,
Now, I know I haven't considered energy leaving the system. However, I'm working on a container that will minimize this. Only looking at an assumption that energy is constant within the system, is my math correct?
Q = mc∆T
m= 1000 grams (slightly more than a quart)
c = 3.98 (in the polluted water that I am handling, since I'm distilling it).
∆T = 75 degrees C, because from 100 degrees celsius to 25 degrees (room temp), is 75 degrees.
Keep in mind, I'm not bothering about heat of vaporization here, I'm just raising it to that temperature and then adding a couple of arbitrary minutes.
Q = 298500
Insolation of sun =1000 W / m^2
1 inch mirror tile = 6.45 cm ^2 = 6.45 * 10^4 m^2
Solar energy in a one inch mirror tile = 0.645 W (found by proportions).
Thus, 289000 = 0.645 J/s (time) (number of mirror tiles)
462790.697 = (time) ( number of mirror tiles)
Now, I put in 500 mirror tiles. I'll probably linear program it later (Never mind, I did linear program it, got about 500, give or take. I can't rely on my mental linear programming :) ) That leaves me with 925.5 seconds, or about 15 minutes. That isn't bad, all things considered,
Now, I know I haven't considered energy leaving the system. However, I'm working on a container that will minimize this. Only looking at an assumption that energy is constant within the system, is my math correct?