Cylindrical and Spherical Coordinates Changing

Click For Summary

Homework Help Overview

The discussion revolves around converting coordinates from spherical to cylindrical and Cartesian systems, specifically focusing on the interpretation of the variables used in these coordinate systems.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are checking the correctness of their conversion attempts and questioning the definitions of the variables used, particularly the use of ##r## and ##\phi##. There is a discussion about the conventions for angles in spherical coordinates and the implications of negative values for ##r## and ##\phi##.

Discussion Status

Multiple interpretations of the coordinate systems are being explored, with some participants suggesting that the answer key may be incorrect while others provide insights into the implications of negative coordinates. Guidance has been offered regarding the reflection of points in polar coordinates.

Contextual Notes

There is uncertainty regarding the conventions used for spherical coordinates, particularly the definitions of ##\theta## and ##\phi##, and how negative values affect the interpretation of these coordinates.

theBEAST
Messages
361
Reaction score
0

Homework Statement


Convert the following as indicated:

1. r = 3, θ = -π/6, φ = -1 to cylindrical

2. r = 3, θ = -π/6, φ = -1 to cartesian

The Attempt at a Solution


I just want to check if my answers are correct.

1. (2.52, -π/6, 1.62)
2. (-2.18, -1.26, 1.62)
 
Physics news on Phys.org
theBEAST said:

Homework Statement


Convert the following as indicated:

1. r = 3, θ = -π/6, φ = -1 to cylindrical

2. r = 3, θ = -π/6, φ = -1 to cartesian

The Attempt at a Solution


I just want to check if my answers are correct.

1. (2.52, -π/6, 1.62)
2. (-2.18, -1.26, 1.62)

What coordinate system are these given in? ##r## is usually used in cylindrical coordinates and ##\rho## for spherical. Also, if ##\phi## is the spherical coordinate angle from the ##z## axis, it is usually restricted to the interval ##[0,\pi]##. Are you sure you copied the ##\phi## values correctly?
 
Mathematicians and physicists use ##\theta## and ##\phi## differently. You need to tell us which convention you're using here.
 
Here is the question with the answer key:
cIwN3.png


In this case r = ρ and I'm not sure why phi is negative.

I don't think the answer key is correct.
 
The answer key is correct. You need to show us your calculations. To answer #1, it's probably most straightforward if you do #2 first and the convert from Cartesian to cylindrical.
 
vela said:
The answer key is correct. You need to show us your calculations. To answer #1, it's probably most straightforward if you do #2 first and the convert from Cartesian to cylindrical.

For number one, how can r be negative? They have -2.52 whereas I have 2.52. It is why I thought the answer key was wrong.
 
When r is negative, you reflect through the origin from where you'd otherwise be. In polar coordinates, for instance, the point r=-1, θ=π/4 would correspond to (-1/√2, -1/√2), which is where you'd end up if you reflected r=1, θ=π/4 through (0,0).

You'll notice they gave you a second answer where r is positive, but the angle has been changed to account for the reflection.
 
vela said:
When r is negative, you reflect through the origin from where you'd otherwise be. In polar coordinates, for instance, the point r=-1, θ=π/4 would correspond to (-1/√2, -1/√2), which is where you'd end up if you reflected r=1, θ=π/4 through (0,0).

You'll notice they gave you a second answer where r is positive, but the angle has been changed to account for the reflection.

Lastly, when ρ is negative does that mean the angle starts from the -z axis? Because when ρ is positive it starts from the positive z axis.
 
Not exactly. Reflection in spherical coordinates takes ##\phi \to \pi-\phi## and ##\theta \to \theta+\pi##. The change to ##\phi## effectively means you're measuring from the -z-axis, but you also have to accompany it with a rotation by 180 degrees about the z-axis.
 

Similar threads

  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K