Cylindrical Capacitor Computation

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The discussion focuses on the computation of cylindrical capacitors, particularly when the length (L) is less than or equal to the outer radius (b). It questions whether the standard equations for cylindrical capacitors still apply in this scenario and discusses the implications of dielectric materials, specifically myelin, on capacitance. The relationship between capacitance, signal velocity, and amplitude in nerve signals is explored, emphasizing that lower capacitance is preferable for faster signal transmission. Participants also note that the electric field calculations rely on Gauss' law, which assumes L is significantly greater than b. The conversation highlights the complexities of modeling these systems accurately.
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The first equation for a cylindrical capacitor is correct, and is written for an air-filled capacitor (no dielectric).

the equation for a dielectric-filled cylindrical capacitor is

C = 2 pi ek e0 L / Ln(b/a) Farads

where ek == dielectric constant of membrane (unitless)
e0 == 8.85 x 10-12 Farads per meter
L == length of capacitor in meters
Ln(x) == natural log of x
b, a == outer and inner radii in meters
=======Homework=====
Check consistency of all units in above equation
Look up the dielectric constant of mylar (DuPont)
Compare to dielectric constant of a myelinated nerve
Look up the description of multiple sclerosis
Look up the definition and description of demyelination
 
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Bob S said:
=======Homework=====
Check consistency of all units in above equation
Look up the dielectric constant of mylar (DuPont)
Compare to dielectric constant of a myelinated nerve
Look up the description of multiple myeloma
Look up the definition and description of demyelination

The two last homework lines aren't necessary at all since I'm a health professional. :wink:
I understand the first one and may compare the two dielectric constants but myelinated/unmyelinated dielectric vary with authors.

What happens when b grows toward the value of L?

Edit: I found a dielectric value for myelin around 6 to 10.
 
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somasimple said:
What happens when b grows toward the value of L?

Edit: I found a dielectric value for myelin around 6 to 10.
RE What happens when b grows toward L? This is a difficult 3-D problem, so I looked in my favorite E&M book (Smythe) but could not find a good answer. My suggestion is if L< b then replace L with b.

I will make a few comments about signal transmission lines and capacitance, and I will try to make them applicable to nerve signals. There are two basic types of analog transmission lines (delay lines) used by engineers: The L - C transmission line (usually dispersionless) and the R - C delay line (usually dispersive). In both types, the signals travel through the series components; L (inductance), or R (resistance), or axons or schwann cells. In all types the capacitance C is between the center conductor (axon or schwann cells) and the outer ground conductor, separated by a space between a and b (insulating dielectric or myalin sheath).

The signal velocity along the center conductor (along axons) is proportional to 1/sqrt(LC) or 1/(RC), and the signal amplitude (voltage or spikes) is proportional to sqrt(L/C) or (1/C). For high amplitude signals and for faster signals, a low capacitance is better. The capacitance for a given geometry (given a, b, L) is proportional to the dielectric constant: Air = 1. mylar (duPont sheets) = 3.2, myelin sheath around axon = 6 to 10, and water = 80. So to preserve both fast nerve signals and high amplitude signals (for given a, b, and L), air is best, followed by mylar, myelin sheath, and water (worst). For a given L and a, larger b is better (but scales only as Ln (a/b))
I hope this helps.
 
somasimple said:
What happens when L is <= b? Does the computation change?
The electric field was calculated by applying Gauss' law to an infinite cylinder. Which is why L must be >> than b.
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capcyl.html"
 
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Bob S said:
The signal velocity along the center conductor (along axons) is proportional to 1/sqrt(LC) or 1/(RC), and the signal amplitude (voltage or spikes) is proportional to sqrt(L/C) or (1/C). For high amplitude signals and for faster signals, a low capacitance is better. The capacitance for a given geometry (given a, b, L) is proportional to the dielectric constant: Air = 1. mylar (duPont sheets) = 3.2, myelin sheath around axon = 6 to 10, and water = 80. So to preserve both fast nerve signals and high amplitude signals (for given a, b, and L), air is best, followed by mylar, myelin sheath, and water (worst). For a given L and a, larger b is better (but scales only as Ln (a/b))
I hope this helps.

Thanks Bob but I simulated the lines with Micro Cap 9 (http://www.spectrum-soft.com/index.shtm" ) and I found effectively the same values of a signal dampening. There is a low pass filtering and, of course, a lower capacitance helps to enhance the cut-off frequency of the filter. But enhancing the limit of the filter doesn't give any mean to enhance the velocity of a signal, I think?
Secondly, the cut-off frequencies are around 10/50 Hz and the the mean sinusoidal frequency (first harmonic) of a firing neuron is often > http://en.wikipedia.org/wiki/Action_potential#Taxonomic_distribution_and_evolutionary_advantages" but it is very well transmitted. It's a kind of huge contradiction.

dlgoff said:
The electric field was calculated by applying Gauss' law to an infinite cylinder. Which is why L must be >> than b.
http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capcyl.html"
That's why I asked
 
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