Cylindrical section is an ellipse?

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Prove or disprove: The intersection of the plane [tex]x+y+z=1[/tex] and the cylinder [tex]x^2+y^2=1[/tex] is an ellipse.
 
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If you perform a change of variables so that the x+y+z=1 plane is the new 'x-y plane' then do you not get a new equation for your cylinder? You can then work it out by setting the new 'z' to zero?
 
The intersection of the two figures is the values of (x, y, z) that satisfy both equations simutaneously so solve the two equations simultaneously: From the first equation, y= 1- x- z. What do you get when you replace y by that in your second equation?
 
Thanks for the help... I actually found a (more general) proof in a geometry textbook (Geometry and the Imagination by David Hilbert)
 
It would have to be an ellipse because the plane isn't parallel to the cylinder. The normal vector is i+j+k which makes an angle of [tex]cos\alpha =\frac{1}{\sqrt3}[/tex] with all three axes.