Conic sections: Can focal points be outside the ellipse?

Bipolarity
Can an ellipse's focal points be outside the ellipse? I have tried googling this, but without any good explanations or answers.

According to my calculations, the focal points of the ellipse defined by $x^{2} + \frac{y^{2}}{4} = 1$ are $(-\sqrt{3},0) (\sqrt{3},0))$.

I maybe wrong of course, but does this mean that the focal points of an ellipse can indeed be outside the ellipse?

BiP

Gold Member
Can an ellipse's focal points be outside the ellipse? I have tried googling this, but without any good explanations or answers.

According to my calculations, the focal points of the ellipse defined by $x^{2} + \frac{y^{2}}{4} = 1$ are $(-\sqrt{3},0) (\sqrt{3},0))$.

I maybe wrong of course, but does this mean that the focal points of an ellipse can indeed be outside the ellipse?

BiP

The focal points of an ellipse are always interior. In a plane, an ellipse is the set of points that are equidistant to two points.

Homework Helper
Can an ellipse's focal points be outside the ellipse? I have tried googling this, but without any good explanations or answers.

According to my calculations, the focal points of the ellipse defined by $x^{2} + \frac{y^{2}}{4} = 1$ are $(-\sqrt{3},0) (\sqrt{3},0))$.

I maybe wrong of course, but does this mean that the focal points of an ellipse can indeed be outside the ellipse?

BiP
Yes, that's wrong. If an ellipse is given by
$$\frac{x^2}{a^2}+ \frac{y^2}{b^2}= 1$$
with b> a, then the foci are at (0, c) and (0, -c) with $c^2= a^2- b^2$
so the foci of this ellipse are on the y-axis, not the x-axis.