[tex]\int_{0}^{x3} ln(t^2 + 1) dt[/tex](adsbygoogle = window.adsbygoogle || []).push({});

^take the derivative of that...sorry the upper-limit is x^{3}NOT2x.

how is the answer 3x^{2}ln (x^{6}+ 1) ?

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# Homework Help: D/dx of the integral from 0 to x^3 of ln(t^2 + 1)

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