Damped Oscillation Homework: Calculating b & Q for Lightly Damped System

Click For Summary
SUMMARY

The discussion focuses on calculating the damping constant (b) and quality factor (Q) for a lightly damped oscillator with mass m=1.6 kg and spring constant s=20 N/m. The damping constant b is confirmed to be 0.796 kg/s, and the quality factor Q is calculated as 7.1066 kg-1. The system is determined to be lightly damped since the damped frequency (\omega') is 99% of the undamped frequency (\omega). The participants clarify that lightly damped systems oscillate with decreasing amplitude but are not critically damped or overdamped.

PREREQUISITES
  • Understanding of damped oscillators and their equations
  • Familiarity with the concepts of damping constant and quality factor
  • Knowledge of the relationship between damped frequency and undamped frequency
  • Basic proficiency in solving differential equations related to oscillatory motion
NEXT STEPS
  • Learn how to derive the critical damping constant for a given mass and spring constant
  • Explore the mathematical formulation of displacement in damped oscillators
  • Study the implications of varying the damping constant on system behavior
  • Investigate real-world applications of damped oscillators in engineering
USEFUL FOR

Students studying mechanical vibrations, physics enthusiasts, and engineers involved in designing systems with oscillatory motion.

razor108
Messages
3
Reaction score
0

Homework Statement


A damped oscillator of mass m=1,6 kg and spring constant s=20N/m has a damped frequency of \omega' that is 99% of the undamped frequency \omega.

As found out by me:
The damping constant b is 0.796 kg/s.
Q of the system is 7.1066 kg^-1.
Are the units here right?

The questions are:
a) Confirm that the system is lightly damped.
b) What new damping constant b_new is required to make the system critically damped?
c) Using b_new calculate the displacement of the mass at t=1,0s given that the displacement is zero and the velocity is 5,0 m/s at t=0.


Homework Equations


To calculate b I used
\omega' = ( \omega^2 - b/2m)^1/2


To calculate Q I used
Q = ((mass*spring constant)^1/2)/b


The Attempt at a Solution



I couldn't find any specific definition of when a system is lightly damped.
I found somewhere that if \omega' is about equal to \omega the system is lightly damped, which is the case here (\omega' = 99%\omega) but this can't be the answer since I have to find a new damping constant.

If I had the new damping constant I would just use the given data to make up a wave equation for x(t).

Thanks for helping.
 
Physics news on Phys.org
To calculate b I used
\omega' = ( \omega^2 - b/2m)^1/2

I think this should be \omega' = \sqrt{\omega^2 - (\frac{b}{2m})^2}

I couldn't find any specific definition of when a system is lightly damped.

I think lightly damped means the same and underdamped. It just means the system is not critically damped or overdamped. So it is just damped enough that the amplitude decreases exponentially over time but still oscillates.

I found somewhere that if \omega' is about equal to \omega the system is lightly damped, which is the case here (\omega' = 99%\omega) but this can't be the answer since I have to find a new damping constant.

But in that part of the question you are supposed to find the new damping constant that would make the system critcally damped, that's a different situation.

Hope that helps.
 

Similar threads

Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
5K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
9
Views
2K
Replies
8
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K