De Broglie relation - new student

Click For Summary
SUMMARY

The discussion centers on the De Broglie relation and the Photoelectric effect, specifically addressing the concept of photon energy and its interaction with electrons. The user questions whether multiple low-energy photons can collectively excite an electron, referencing the equation E = hf. The consensus confirms that multiphoton processes are feasible under non-linear optics, provided the photon intensity is sufficiently high. This indicates that energy absorption is contingent on the atom's perspective of the photon energy.

PREREQUISITES
  • Understanding of the De Broglie relation
  • Familiarity with the Photoelectric effect
  • Knowledge of multiphoton processes in quantum mechanics
  • Basic principles of non-linear optics
NEXT STEPS
  • Research "Two-photon absorption" in non-linear optics
  • Explore the implications of "E = hf" in quantum mechanics
  • Study the effects of "Doppler shift" on photon frequency
  • Investigate "quantum energy storage mechanisms" in atomic systems
USEFUL FOR

Students of physics, particularly those studying quantum mechanics, as well as educators and researchers interested in the interactions between light and matter.

mainguy
Messages
15
Reaction score
0
Hi physics folk,

Thought you guys would be able to clarify something, self study learner here getting into quantum.
So I've just learned about the De Broglie relation and The Photoelectric effect and am bamboozled (in a good way).

The notion being that light is absorbed in packets. However I'm unclear on this, if E = hf, surely you could arrange four photons (each with 1/4 of the excitation energy of the electron) so they overlap perfectly on the electron and thus excite it, or is it literally impossible in any scenario?

Also I was thinking about whether this quantum property is intrinsic to light. If you have an atom moving relative to an observer at 0.5c, away from a beam of photons shining on the atom, then the observer notes that the moving atom sees a frequency given by the classic doppler shift, e.g. Photons with a lower frequency.

Meanwhile in the atom's frame it notes a different frequency, given by the special relativistic doppler shift. That is, the two disagree on the photons striking the electron.

However if we add the time dilation factor to the observer frame the agreement is of course perfect. However does this not indicate that the wave packet energy is not intrinsic to the wave, that is waves of a different frequency can appear to create the same excitation?
 
Physics news on Phys.org
In order for 4 low-energy photons to create the same effect as 1 hi-energy photon, the electron orbital would have to have some way of storing the energy - even for only a femtosecond. No such mechanism exists.

As for your second question: it's all about the available energy. So what counts is what the atom sees. If we see a low-energy photon, but it sees a high-energy one, that higher energy will be available to the electron.
 
mainguy said:
The notion being that light is absorbed in packets. However I'm unclear on this, if E = hf, surely you could arrange four photons (each with 1/4 of the excitation energy of the electron) so they overlap perfectly on the electron and thus excite it, or is it literally impossible in any scenario?
Multiphoton processes are indeed possible, see https://en.wikipedia.org/wiki/Two-photon_absorption. Such effects belong to non-linear optics and occur only at sufficiently high intensities.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
5K
  • · Replies 28 ·
Replies
28
Views
8K
Replies
1
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K