De Broglie wavelength of an electron

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SUMMARY

The de Broglie wavelength of an 8 MeV proton is calculated using the formula y = h/p, where h is Planck's constant and p is the momentum. The momentum is derived from the kinetic energy (K = 8 MeV) and the rest mass energy (Eo = 938.3 MeV). The calculations yield a velocity of approximately 0.1298c and a momentum of 121749577.6 eV/c, resulting in a de Broglie wavelength of 1.133 x 10^-22 nm. The discussion highlights a common error in the momentum calculation, specifically the omission of the speed of light (c) in the final momentum expression.

PREREQUISITES
  • Understanding of de Broglie wavelength concept
  • Familiarity with relativistic energy equations
  • Knowledge of Planck's constant (h = 4.136 x 10^-15 eV·s)
  • Basic principles of momentum (p = mv)
NEXT STEPS
  • Review relativistic momentum calculations
  • Study the implications of kinetic energy in particle physics
  • Explore the relationship between energy and wavelength in quantum mechanics
  • Learn about the significance of Planck's constant in quantum theory
USEFUL FOR

Students and educators in physics, particularly those focusing on quantum mechanics and particle physics, will benefit from this discussion. It is also useful for anyone involved in calculations related to particle wavelengths and energies.

Oijl
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Homework Statement


Find the de Broglie wavelength of an 8 MeV proton.


Homework Equations


y = h/p
where y is the wavelength
p = mv
K = Eo/sqrt(1-v^2/c^2)
where Eo is the rest mass and K is the kinetic energy


The Attempt at a Solution


I make the assumption that "an 8 MeV proton" is an proton with a kinetic energy of 8 MeV.

I know K = 8 MeV and Eo = 938.3 MeV. So I solve for v, get

v = sqrt(1 - (Eo/(K+Eo))^2)c = 0.1297554914c

I know m = 938.3 MeV/c^2. So I plug into p = mv and get

p = 121749577.6 eV/c

I know h = 4.136*10^-15 eV*s. So I plug into y = h/p and get

y = 3.397*10^-23 s*c

But I want nanometers, so since I know that c has units of m/s, I divide by the numerical value of c and multiply by 10^9 so that

y = 1.133*10^-22 nm

But this much too small, isn't it? Where am I going wrong?
 
Physics news on Phys.org
"I know m = 938.3 MeV/c^2. So I plug into p = mv and get

p = 121749577.6 eV/c"

I think you left out a "c".

ehild
 

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