Debroglie wavelength of a baseball

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michael879
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ok can someone please explain to me why this is wrong? debroglie of a baseball weighing 1kg is h/(1kg * v). You through this at a double slit at 10^-34 m/s which makes the wavelength equal to 6.63 meters. for a double slit its d*sin(theta) = m * (wavelength) so you get theta = sin^-1(6.63/d). If the distance between the slits is 12 meters, you get a theta of 33.5 degrees for the first maxima. After sending a lot of baseballs through there should be a very noticeable diffraction pattern right? I know this would take 3 * 10 ^26 years to get one baseball through, but it could be done with something smaller than a baseball that's still visible.. and anyway, it can't be true that there would be a diffraction pattern from this. I mean, baseballs being shot at two slit that's are 12 meters apart? theyre going to hit the part in between them right?
 
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michael879 said:
ok can someone please explain to me why this is wrong? debroglie of a baseball weighing 1kg is h/(1kg * v). You through this at a double slit at 10^-34 m/s which makes the wavelength equal to 6.63 meters. for a double slit its d*sin(theta) = m * (wavelength) so you get theta = sin^-1(6.63/d). If the distance between the slits is 12 meters, you get a theta of 33.5 degrees for the first maxima. After sending a lot of baseballs through there should be a very noticeable diffraction pattern right? I know this would take 3 * 10 ^26 years to get one baseball through, but it could be done with something smaller than a baseball that's still visible.. and anyway, it can't be true that there would be a diffraction pattern from this. I mean, baseballs being shot at two slit that's are 12 meters apart? theyre going to hit the part in between them right?

What's the uncertainty in position when you know that the baseball is moving at 10^(-34)m ?
 
you don't know exactly how fast it is moving. In fact, the uncertainty of the speed is higher than the position since u can see the thing.