Decomposing the arc length of a circular arc segment

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SUMMARY

The discussion focuses on calculating the distances covered by a particle traveling along a circular arc segment defined by a radius R, start angle θ1, and end angle θ2. The total arc length is given by the formula L = R(Δθ), where Δθ = θ2 - θ1. Participants suggest breaking the arc into segments at quadrant crossings to analyze the distances along the X and Y axes separately. The goal is to derive a single elegant expression for both X and Y distances, although this may not be feasible due to the nature of circular motion.

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  • Understanding of circular motion and arc length calculations
  • Familiarity with Cartesian coordinates and trigonometric functions
  • Basic knowledge of integrals and calculus
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jumbo1985
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A particle travels along a circular arc segment centered at the origin of the Cartesian plane with radius R, a start angle θ1 and an end angle θ2 (with θ2 ≥ θ1 and Δθ = θ2 - θ2 ≤ 2π). The total distance traveled is equal to the arc length of the segment: L = R(Δθ).

I would like to find the distance covered by the particle along the X axis and the distance covered by the particle along the Y axis.

I'm not sure how to do this unless I break up the arc at each quadrant crossing and analyze the pieces separately.

Any tips are greatly appreciated.
 
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Distance covered as in "if you go back and forth you count it twice"? You can write down an integral that works in general, but analyzing 2 special cases is easier.
 
Yes, exactly - If you go back and forth you count it twice. I'm looking for one elegant expression in terms of x and in terms of y but that may not be possible?
 
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