Decomposing the direct sum as direct product

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SUMMARY

The discussion focuses on the decomposition of the direct sum as a direct product in the context of angular momentum in quantum mechanics, specifically addressing the equation \( j \otimes s = \bigoplus_{l=|s-j|}^{|s+j|} l \). The strategy for proving this general statement involves counting the number of states in the spin representations, as outlined in Cohen-Tannoudji's second volume. The Clebsch-Gordan theorem for SU(2) is also referenced as a foundational concept for understanding this decomposition. The participants emphasize the importance of grouping states by definite j values to achieve the correct representation.

PREREQUISITES
  • Understanding of angular momentum in quantum mechanics
  • Familiarity with the Clebsch-Gordan theorem for SU(2)
  • Knowledge of spin representations and their state counting
  • Basic concepts of group theory as applied to physics
NEXT STEPS
  • Study the Clebsch-Gordan coefficients in detail
  • Explore the applications of SU(2) in quantum mechanics
  • Review the second volume of Cohen-Tannoudji's text for deeper insights
  • Learn about the implications of angular momentum coupling in quantum systems
USEFUL FOR

Students and researchers in quantum mechanics, particularly those focusing on angular momentum and spin representations, will benefit from this discussion.

elduderino
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This is a basic question in angular momentum in quantum mechanics that I am studying.
I know that [tex]\frac{1}{2}\otimes \frac{1}{2} = 1\oplus 0[/tex] What would be a strategy to proving the general statement for spin representations [tex]j\otimes s =\bigoplus_{l=|s-j|}^{|s+j|} l[/tex]
 
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This is typically treated in every book of quantum mechanics. Use for example the second volume of Cohen - Tannoudji's text. The famous grid-proof is there. Or any books on group theory with applications to physics (this is typically the Clebsch-Gordan theorem for SU(2)).
 
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elduderino, The decomposition can be obtained just by counting the number of states. A system with spin s has 2s + 1 states, one for each value of m running from m = s, s-1,... down to m = -s. Now look at the states in the product ℓ ⊗ s. There will be one state with m = ℓ+s, two states with m = ℓ+s-1, ... down to s states with m = ℓ-s (assuming s <= ℓ). If you try grouping these states into sets with definite j values, you will find it necessary to use j = ℓ+s, ... down to j = ℓ-s, and each of these j values will be needed exactly once.
 

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