Defining principal strain + direction

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SUMMARY

The discussion focuses on defining principal strains and directions from a given strain tensor represented as: 0.9 0 0; 0 -0.4 0.2; 0 0.2 0.6. The participants calculated the invariants I1, I2, and I3, arriving at values of I1 = 1.1, I2 = 0.1, and I3 = -0.252. The challenge lies in determining the roots of the cubic equation ε^3 - I1ε^2 - I2ε - I3 = 0, which is essential for identifying principal strains. The discussion highlights the importance of correctly substituting tensor values to achieve accurate results.

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Homework Statement


Question: The strain state in a point is defined by the tensor:
0.9 0 0
0 -0.4 0.2
0 0.2 0.6
- Define principal strains and directions in the point
- Explain how deforms the element shown in figure 2b (they just drew a cube on 3d axis)
- Draw the principal directions



Homework Equations


So i know that ε^3 - I1ε^2 - I2ε - I3 = 0



The Attempt at a Solution


and for the I values, i subbed the tensor values in and got I1 = 0.7, I2 = 0.02, I3 = -0.252
I have a feeling I'm subbing the wrong values though. is εx = εxx from the tensor above?
because the end equation i get, does not give me any roots.
 
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I think you have a good feeling. For example, I1 = 0.9 - 0.4 + 0.6 = 1.1 .
 
ahh indeed I've got 2 values wrong.
So now i got I1 = 1.1, I2 = 0.1 and I3 = -0.252, but i still can't find my roots?
 

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