Definite Integral Help: Solving from 0 to 2 in t and t^2 with Norm ||t,t^2||dt

[jcamp11]

Need help solving the definite integral from 0<x<2 ||t,t^2||dt ( || = the norm of.)

so it really is

int. (t^2, t^4)^(1/2)

please and thank you.. i don't know why i can't get this.. but hellp pleaseee

 

[malawi_glenn]

You must show work done/attempt to solution before we help you.

Also can you provide more info here, x is from 0 to 2, but your variable of integration is t.. And what is "int. (t^2, t^4)^(1/2)" ?

 

[jcamp11]

You must show work done/attempt to solution before we help you.

Also can you provide more info here, x is from 0 to 2, but your variable of integration is t.. And what is "int. (t^2, t^4)^(1/2)" ?

im sorry, t is from 0 to 2, used to writing x.. doesn't really matter what the variable is tho..

int. (t^2, t^4)^(1/2) is just stating the integral of that function... hence "int." for INTegral

what i have gotten for an answer the first time attempted i used U substitution pulling out a t^2 leaving me with t^2(1+t^2) which is wrong.. because this question was on an exam and he marked an x on that part.. i don't konw how to proceed from there

 

[Dick]

So the problem is to integrate (t^2+t^4)^(1/2). That's ((t^2)*(t^2+1))^(1/2)=t*(t^2+1)^(1/2). What comes to mind as a u substitution?